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System of Equations: 3x + y = -9, -3x - 2y = 12

Learn how to solve a system of equations algebraically using the elimination method. Practice problems and examples are provided.

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System of Equations: 3x + y = -9, -3x - 2y = 12

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  1. 4x + 2y = 4 6x + 2y = 8 Bell-work 10/14/2014 Multiple Choice: Which set of ordered pairs is a solution to the system? A. (7,5) B. (2,4) C. (2,-2) D. (-1,3) What type of system is this?

  2. Solving Systems Algebraically 3-2 Solving Systems Algebraically pg 125

  3. 3x + y = –9 –3x – 2y = 12 3x + y = –9 –3x – 2y = 12 Two terms are additive inverses, so add. –y = 3 Solve for y. Solving Systems Algebraically Lesson 3-2 Additional Examples Use the elimination method to solve the system. y = –3 3x + y = –9 Choose one of the original equations. 3x + (–3) = –9 Substitute y.Solve for x. x = –2 The solution is (–2, –3).

  4. x + y = 12 x – y = 2 Solving Systems Algebraically Lesson 3-2 Use the elimination method to solve the system

  5. –3x + 5y = 6 6x – 10y = 0 –6x + 10y = 12 6x – 10y = 0 Multiply the first line by 2 to make the x terms additive inverses. 0 = 12 Solving Systems Algebraically Lesson 3-2 Additional Examples Solve each system by elimination. a. –3x + 5y = 6 6x – 10y = 0 The two equations in the system represent parallel lines. The system has no solution.

  6. 2a + 3b = 12 5a - b = 13 Solving Systems Algebraically Lesson 3-2 You Try! Use the elimination method to solve the system

  7. –3x + 5y = 6 6x – 10y = –12 –6x + 10y = 12 6x + 10y = –12 Multiply the first line by 2 to make the x terms additive inverses. 0 = 0 Solving Systems Algebraically Lesson 3-2 Additional Examples On your index card solve: b. –3x + 5y = 6 6x – 10y = –12 The two equations in the system represent the same line. The system has an infinite number of solutions.

  8. Solving Systems Algebraically Homework pg 128 18-39 Every 3rd

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