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Dive into the principles of conservation of energy, work done by forces, and various forms of energy like kinetic and potential energy. Learn essential concepts such as Hooke's Law, elastic potential energy, and the Work-Energy Theorem. Explore examples and calculations to understand energy transformation and its applications in real-world scenarios.
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Chapter 6: Conservation of Energy • CQ: 1, 3. Problems: 1, 3, 5, 11, 17, 25, 29, 32, 49, 51, 53, 69, 71. • Law of Conservation of Energy • Work done by a constant force • Kinetic energy • Gravitational potential energy • Work by variable force, Hooke’s law • Elastic potential energy
Energy & Work Energy is the capacity to do work, Energy is position & speed dependent Unit: joule = newton·meter (J = N·m) Work = force x distance (Fd) when force is in direction of motion (or opposite to motion) Ex. 50N pushes distance of 4 meters. W = (50N)(4m) = 200 J / 2
Work & Force • Work is energy transferred by part of force in line of motion • Ex. Force 60° above path of motion
Machines change an applied force by increasing it, decreasing it, or changing its direction. Types: inclined plane, screw, wedge pulley, wheel lever 4
levers Work input Fd = Work output Fd Ex. Your hand moves 100m, causes car to rise 0.10m. The force amplification factor is, F d __ __ = F d
inclined plane Weight x height change = Force x distance along plane Force along ramp less than Weight Ramp distance greater than height change ADA Standards: Ramp must be at least 12x longer than vertical rise Ex. A 1ft vertical rise requires 12ft of ramp. 6
ADA Ramp 7
Energy of Motion Called Kinetic Energy (KE) KE = ½(mass)(velocity)2 = ½mv2. Ex. 2000kg car moving at 2m/s. KE = ½ (2000)(2)2 = 4000J. Position Dependent Energies are called Potential Energies “PE” or “U” / 8
Gravitational Potential Energy • U = weight x height (mgh) • 1kg at 1m height: • U = (1kg)(9.8N/kg)(1m) = 9.8J • Energy released in falling • /
Hooke’s Law • The restoring force an object exerts is proportional to the amount it has been deformed (F = -kx)
Elastic Potential Energy • PE-elastic = average force x distance • 10N compresses a spring 1m. U = (avg. force, 5 N)(1m) = 5 J • k = spring constant = force/distance • U = (½kx)x = ½kx2
Work Energy Theorem Let direction of motion be +x
Power Power is the rate work is performed Power = work/time = Force x velocity Unit: watt = joule/second = J/s Other Unit: horsepower 1 horsepower = 746 watts / 13
Energy & Power Energy = power x time Ex. A toy car has 1000 J of energy at full charge. How long can it run at 100 watts? At 10 watts? Time = Energy/power = 1000J/100watts = 10 seconds = 1000J/10watts = 100 seconds/ 14
Conservation of Energy • E = K + U = constant • Ex. Falling: Kinetic ↑ as Potential ↓ • /
K E Ug
Energy Summary • PE-gravitational = mgy • PE-elastic = ½kx2 • KE = ½mv2 • Mechanical Energy ME = KEs + PEs • E = ME + Thermal Energy
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y y Energy and speed are same at height y Accelerations are not same
d Ex. Sled slides to a stop
1 5 2 4 3 A 2.00kg ball is dropped from rest from a height of 1.0m above the floor. The ball rebounds to a height of 0.500m. A movie-frame type diagram of the motion is shown below.
Terminology • E: total energy of a system • E-mech = total energy minus the thermal energy • E-mech = E – Utherm. • Mech. Energy conserved in a frictionless system
Power: The time rate of doing work. SI Unit: watt, W = J/s Example: How much average power is needed to accelerate a 2000kg car from rest to 20m/s in 5.0s? work = DKE
Another equation for Power: Ex: A car drives at 20m/s and experiences air-drag of 400N. The engine must use (400N)(20m/s) = 8,000 watts of engine power to overcome this force. 8,000 watts = 10.7 hp.
Work Example Moving down an inclined plane mgsinq mg h mg d q (mgsinq)d = mg(dsinq) = mgh
Summary • Energy: Kinetic + Potential + Thermal, is conserved. • Mech. Energy: Kinetic + Potential, conserved in frictionless systems • Work is energy transfer (+ or -) • Power is rate of energy transfer
Vehicle Efficiency 1 gallon gasoline has 138,000,000 J Engines only get a fraction of this: Ex. A 25% efficient car gets (0.25)(138,000,000 J) = 34,500,000J out of 1 gallon. A 20% efficient car gets 27,600,000J. 27
Vehicle Frictional Work = Total Frictional Force x distance Ex. 400N friction for 1600 meters (1 mile) Work = (400N)(1600m) = 640,000J for one mile traveled /
Ex. Mpg 20% Efficiency, f = 400N Engine gets 27,600,000 J/gal Frictional Work/Mile = 640,000J/mile = 43 mpg (at constant speed) 30
Horsepower: 1 hp = 746 watts For the previous example:
What size electric motor is needed to raise 2000lbs = 9000N of bricks at 10cm/s? Minimum Power: Pavg = Fvavg = (9000N)(0.1m/s) P = 900 W = 1.2 hp
Similar to 5-45. • 3gram bullet moves at 200m/s and goes 10cm into a tree. What is the average force on the bullet? Tree? • Wnet on bullet = -Fd = change in K • Change in K = 0 – ½ (0.003kg)(200)(200) • -F(0.1m) = - 60Nm • F = 600N
By energy conservation, the sum of all energies in each column is the same, = E1 = mg(1) = 19.6J Calculate v2: (use 1st and 2nd columns) mg(1) = ½ m(v2)2. g = ½ (v2)2. v2 = 4.43m/s Calculate PE-thermal: (use 1st and 5th columns) mg(1) = mg(1/2) + PE-thermal mg(1/2) = PE-thermal PE-thermal = 9.8J 37
Calculate PE-elastic: (use 1st and 3rd columns) PE-elastic + PE-thermal = mg(1) PE-elastic + 9.8 = 19.6 PE-elastic = 9.8J Calculate v4: (use 1st and 4th columns) ½ m(v4)2 + PE-thermal = mg(1) ½ m(v4)2 + 9.8 = 19.6 ½ m(v4)2 = 9.8 (v4)2 = 2(9.8)/2 v4 = 3.13m/s 38