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ELECTRIC POTENTIAL. January 5, 2007. Goings On For the Next Few Days. Today Return Exam #1 Yell at you Start Potential There is a WebAssign Posted Wednesday – More of the same Friday – 7:30 AM problem session Quiz on Potential Class – Potential + problems. Average Grade was 58%.
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ELECTRIC POTENTIAL January 5, 2007
Goings On For the Next Few Days • Today • Return Exam #1 • Yell at you • Start Potential • There is a WebAssign Posted • Wednesday – More of the same • Friday – • 7:30 AM problem session • Quiz on Potential • Class – Potential + problems
If you got less than 50% on this test (remember that I added 10) • You either • Didn’t study for this class (probably from the beginning) • You did study and you should ask yourself if you really have the skills to become an engineer or scientist. • Yes, I am cruel! But think about it.
What were the issues?? • You didn’t understand how to use symmetry and avoid integration (#1) • You added vectors as if they were scalars. (#1 and #2) • You didn’t understand the CONCEPT of FLUX. • You were unable to extract and understand information from a graph.
So … what next?? • I will work with you if you want me to … • Utilize office hours for questions • M 7:30-8:15 • W 7::30 to 9:15ish • F 8:30-8:15 • MOST (not all) MWF 10:30 – 11:30 • By appointment • Come to the Friday session and ask questions • F 7:30-8:20
Picture a Region ofspace Where there is an Electric Field • Imagine there is a particle of charge q at some location. • Imagine that the particle must be moved to another spot within the field. • Work must be done in order to accomplish this.
What (or who) must do this work? • An external agent (person) • The Field itself • Either of the above • Dr. Bindell
Electric Potential • We will be dealing with • Work • Energy & Conservation • Work must be done to move a charge in an electric field. • Let’s do a demo ….
I need some help. Push vs Pull Mrs. FIELDS vs Mr. External
What we will do …. E • For the moment, assume the charge has MASS. (It may not.) • Assume the charge is initially stationary. • The charge is to be moved to the left. • The charge is to be moved at CONSTANT velocity. + charge Mrs. Fields Mr. External
During this process, who is pushing? • Mr. External • Mrs. Fields • Dr. Bindell
When we start the process, the charge that is stationary must be brought up to speed. • This is work and must be accounted for. • This is work but we don’t have to worry about it. • Only Dr. Bindell worries about stupid stuff like this!
Start and Sop • ENERGY is required to bring the charge up to speed (if it has mass). • ENERGY is required to bring the particle back to rest (if it has mass). • The sum of these two is ZERO.
During this process, who is actually doing work? • Mr. External • Mrs. Fields • Both of them • Neither of them.
Clearly • Both are doing work. • BOTH are applying a force through a distance. • BOTH get tired!
About the work that they do .. • Mrs. Fields does more work than Mr. External. • Mr. External does more work than Mrs. Fields. • Both do the same amount of work. • Each does the negative amount of work than the other does.
Each does the negative amount of work than the other does. WHY ?
So, when we move a charge in an Electric Field .. • Move the charge at constant velocity so it is in mechanical equilibrium all the time. • Ignore the acceleration at the beginning because you have to do the same amount of negative work to stop it when you get there.
Summary-- • When an object is moved from one point to another in an Electric Field, • It takes energy (work) to move it. • This work can be done by an external force (you). • You can also think of this as the FIELD doing the negative of this amount of work on the particle.
And also remember: The net work done by a conservative (field) force on a particle moving around a closed path is ZERO!
A nice landscape Work done by external force = mgh How much work here by gravitational field? h mg
IMPORTANT • The work necessary for an external agent to move a charge from an initial point to a final point is INDEPENDENT OF THE PATH CHOSEN!
The Electric Field • Is a conservative field. • No frictional losses, etc. • Is created by charges. • When one (external agent) moves a test charge from one point in a field to another, the external agent must do work. • This work is equal to the increase in potential energy of the charge. • It is also the NEGATIVE of the work done BY THE FIELD in moving the charge from the same points.
A few things to remember… • A conservative force is NOT a Republican. • An External Agent is NOT 007.
Electric Potential Energy • When an electrostatic force acts between two or more charged particles, we can assign an ELECTRIC POTENTIAL ENERGY U to the system. • The change in potential energy of a charge is the amount of work that is done by an external force in moving the charge from its initial position to its new position. • It is the negative of the work done by the FIELD in moving the particle from the initial to the final position.
Definition – Potential Energy • PE or U is the work done by an external agent in moving a charge from a REFERENCE POSITION to a different position. • A Reference ZERO is placed at the most convenient position • Like the ground level in many gravitational potential energy problems.
Zero Level Example: E Work by External Agent Wexternal = Fd = qEd= U Work done by the Field is: Wfield= -qEd = -Wexternal d q F
A uniform electric field of magnitude 290 V/m is directed in the positive x direction. A +13.0 µC charge moves from the origin to the point (x, y) = (20.0 cm, 50.0 cm).(a) What is the change in the potential energy of the charge field system?[-0.000754] J
AN IMPORTANT DEFINITION • Just as the ELECTRIC FIELD was defined as the FORCE per UNIT CHARGE: We define ELECTRICAL POTENTIAL as the POTENTIAL ENERGY PER UNIT CHARGE: VECTOR SCALAR
Let’s move a charge from one point to another via an external force. • The external force does work on the particle. • The ELECTRIC FIELD also does work on the particle. • We move the particle from point i to point f. • The change in kinetic energy is equal to the work done by the applied forces. Assume this is zero for now.
Furthermore… If we move a particle through a potential difference of DV, the work from an external “person” necessary to do this is qDV
Electric Field = 2 N/C d= 100 meters 1 mC Example
Consider Two Plates OOPS …
The difference in potential between the accelerating plates in the electron gun of a TV picture tube is about 25 000 V. If the distance between these plates is 1.50 cm, what is the magnitude of the uniform electric field in this region?
An ion accelerated through a potential difference of 115 V experiences an increase in kinetic energy of 7.37 × 10–17 J. Calculate the charge on the ion.
Important • We defined an absolute level of potential. • To do this, we needed to define a REFERENCE or ZERO level for potential. • For a uniform field, it didn’t matter where we placed the reference. • For POINT CHARGES, we will see shortly that we must place the level at infinity or the math gets very messy!
An Equipotential Surface is defined as a surface on which the potential is constant. It takes NO work to move a charged particle between two points at the same potential. The locus of all possible points that require NO WORK to move the charge to is actually a surface.
Field Lines and Equipotentials Electric Field Equipotential Surface
Components Enormal Electric Field Dx Eparallel Work to move a charge a distance Dx along the equipotential surface Is Q x Eparallel X Dx Equipotential Surface
BUT • This an EQUIPOTENTIAL Surface • No work is needed since DV=0 for such a surface. • Consequently Eparallel=0 • E must be perpendicular to the equipotential surface