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CHAPTER 20

CHAPTER 20. “ Oxidation-Reduction Reactions”. LEO SAYS GER. Pre-AP Chemistry Charles Page High School Stephen L. Cotton. Section 20.1 The Meaning of Oxidation and Reduction (Redox). OBJECTIVES

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CHAPTER 20

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  1. CHAPTER 20 “Oxidation-Reduction Reactions” LEO SAYS GER Pre-AP Chemistry Charles Page High School Stephen L. Cotton

  2. Section 20.1The Meaning of Oxidation and Reduction (Redox) • OBJECTIVES • Define oxidation and reduction in terms of the loss or gain of oxygen, and the loss or gain of electrons.

  3. Section 20.1The Meaning of Oxidation and Reduction (Redox) • OBJECTIVES • State the characteristics of a redox reaction and identify the oxidizing agent and reducing agent.

  4. Section 20.1The Meaning of Oxidation and Reduction (Redox) • OBJECTIVES • Describe what happens to iron when it corrodes.

  5. Oxidation and Reduction (Redox) • Early chemists saw “oxidation” reactions only as the combination of a material with oxygen to produce an oxide. • For example, when methane burns in air, it oxidizes and forms oxides of carbon and hydrogen, as shown in Fig. 20.1, p. 631

  6. Oxidation and Reduction (Redox) • But, not all oxidation processes that use oxygen involve burning: • Elemental iron slowly oxidizes to compounds such as iron (III) oxide, commonly called “rust” • Bleaching stains in fabrics • Hydrogen peroxide also releases oxygen when it decomposes

  7. Oxidation and Reduction (Redox) • A process called “reduction” is the opposite of oxidation, and originally meant the loss of oxygen from a compound • Oxidation and reduction always occur simultaneously • The substance gaining oxygen (or losing electrons) is oxidized, while the substance losing oxygen (or gaining electrons) is reduced.

  8. Oxidation and Reduction (Redox) • Today, many of these reactions may not even involve oxygen • Redox currently says that electrons are transferred between reactants • Mg + S → Mg2+ + S2- • The magnesium atom changes to a magnesium ion by losing 2 electrons, and is thus oxidized • The sulfur atom is changed to a sulfide ion by gaining 2 electrons, and is thus reduced.

  9. Oxidation and Reduction (Redox) Each sodium atom loses one electron: Each chlorine atom gains one electron:

  10. LEO says GER : Lose Electrons = Oxidation Sodium is oxidized Gain Electrons = Reduction Chlorine is reduced

  11. LEO says GER : - Losing electrons is oxidation, and the substance that loses the electrons is called the reducing agent. - Gaining electrons is reduction, and the substance that gains the electrons is called the oxidizing agent. Mg(s) + S(s) → MgS(s) Mg is the reducing agent Mg is oxidized – loses e- S is the oxidizing agent S is reduced – gains e-

  12. Oxidation and Reduction (Redox) • Conceptual Problem 20.1, page 634 • It is easy to see the loss and gain of electrons in ionic compounds, but what about covalent compounds? • In water, we learned that oxygen is highly electronegative, so: • the oxygen gains electrons (is reduced and is the oxidizing agent), and the hydrogen loses electrons (is oxidized and is the reducing agent)

  13. Not All Reactions are Redox Reactions - Reactions in which there has been no change in oxidation number are not redox reactions. Examples:

  14. Corrosion • Damage done to metal is costly to prevent and repair • Iron, a common construction metal often used in forming steel alloys, corrodes by being oxidized to ions of iron by oxygen. • This corrosion is even faster in the presence of salts and acids, because these materials make electrically conductive solutions that make electron transfer easy

  15. Corrosion • Luckily, not all metals corrode easily • Gold and platinum are called noble metals because they are resistant to losing their electrons by corrosion • Other metals may lose their electrons easily, but are protected from corrosion by the oxide coating on their surface, such as aluminum – Figure 20.7, page 636 • Iron has an oxide coating, but it is not tightly packed, so water and air can penetrate it easily

  16. Corrosion • Serious problems can result if bridges, storage tanks, or hulls of ships corrode • Can be prevented by a coating of oil, paint, plastic, or another metal • If this surface is scratched or worn away, the protection is lost • Other methods of prevention involve the “sacrifice” of one metal to save the second • Magnesium, chromium, or even zinc (called galvanized) coatings can be applied

  17. Section 20.2Oxidation Numbers • OBJECTIVES • Determine the oxidation number of an atom of any element in a pure substance.

  18. Section 20.2Oxidation Numbers • OBJECTIVES • Define oxidation and reduction in terms of a change in oxidation number, and identify atoms being oxidized or reduced in redox reactions.

  19. Assigning Oxidation Numbers • An “oxidation number” is a positive or negative number assigned to an atom to indicate its degree of oxidation or reduction. • Generally, a bonded atom’s oxidation number is the charge it would have if the electrons in the bond were assigned to the atom of the more electronegative element

  20. Rules for Assigning Oxidation Numbers • The oxidation number of any uncombined element is zero. • The oxidation number of a monatomic ion equals its charge.

  21. Rules for Assigning Oxidation Numbers • The oxidation number of oxygen in compounds is -2, except in peroxides, such as H2O2 where it is -1. • The oxidation number of hydrogen in compounds is +1, except in metal hydrides, like NaH, where it is -1.

  22. Rules for Assigning Oxidation Numbers • The sum of the oxidation numbers of the atoms in the compound must equal 0. 2(+1) + (-2) = 0 H O (+2) + 2(-2) + 2(+1) = 0 Ca O H

  23. Rules for Assigning Oxidation Numbers • The sum of the oxidation numbers in the formula of a polyatomic ion is equal to its ionic charge. X + 4(-2) = -2 S O X + 3(-2) = -1 N O X = +6 X = +5

  24. Reducing Agents and Oxidizing Agents • Conceptual Problem 20.2, page 641 • An increase in oxidation number = oxidation • A decrease in oxidation number = reduction Sodium is oxidized – it is the reducing agent Chlorine is reduced – it is the oxidizing agent

  25. Trends in Oxidation and Reduction • Active metals: • Lose electrons easily • Are easily oxidized • Are strong reducing agents • Active nonmetals: • Gain electrons easily • Are easily reduced • Are strong oxidizing agents Conceptual Problem 20.3, page 643 Technology & Society – page 644

  26. Section 20.3Balancing Redox Equations • OBJECTIVES • Describe how oxidation numbers are used to identify redox reactions.

  27. Section 20.3Balancing Redox Equations • OBJECTIVES • Balance a redox equation using the oxidation-number-change method.

  28. Section 20.3Balancing Redox Equations • OBJECTIVES • Balance a redox equation by breaking the equation into oxidation and reduction half-reactions, and then using the half-reaction method.

  29. Identifying Redox Equations • In general, all chemical reactions can be assigned to one of two classes: • oxidation-reduction, in which electrons are transferred: • Single-replacement, combination, decomposition, and combustion • this second class has no electron transfer, and includes all others: • Double-replacement and acid-base reactions

  30. Identifying Redox Equations • In an electrical storm, oxygen and nitrogen react to form nitrogen monoxide: • N2(g) + O2(g) → 2NO(g) • Is this a redox reaction? • If the oxidation number of an element in a reacting species changes, then that element has undergone either oxidation or reduction; therefore, the reaction as a whole must be a redox. • Conceptual Problem 20.4, page 647 YES!

  31. Balancing Redox Equations • It is essential to write a correctly balanced equation that represents what happens in a chemical reaction • Fortunately, two systematic methods are available, and are based on the fact that the total electrons gained in reduction equals the total lost in oxidation. The two methods: • Use oxidation-number changes • Use half-reactions

  32. Using Oxidation-Number Changes • Sort of like chemical bookkeeping, you compare the increases and decreases in oxidation numbers. • start with the skeleton equation • Step 1: assign oxidation numbers to all atoms; write above their symbols • Step 2: identify which oxidized/reduced • Step 3: use bracket lines to connect • Step 4: use coefficients to equalize • Step 5: make sure they are balanced for both atoms and charge – Problem 20.5, 649

  33. Using half-reactions • A half-reaction is an equation showing just the oxidation or just the reduction that takes place • they are then balanced separately, and finally combined • Step 1: write unbalanced equation in ionic form • Step 2: write separate half-reaction equations for oxidation and reduction • Step 3: balance the atoms in the half-reactions

  34. Using half-reactions • continued • Step 4: add enough electrons to one side of each half-reaction to balance the charges • Step 5: multiply each half-reaction by a number to make the electrons equal in both • Step 6: add the balanced half-reactions to show an overall equation • Step 7: add the spectator ions and balance the equation • Rules shown on page 651 – bottom • Conceptual Problem 20.6, page 652

  35. Choosing a Balancing Method • The oxidation number change method works well if the oxidized and reduced species appear only once on each side of the equation, and there are no acids or bases. • The half-reaction method works best for reactions taking place in acidic or alkaline solution.

  36. End of Chapter 20

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