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mass spectrometry II. FOS 6355 Summer 2005. Russell Rouseff. Isotope Abundances. 16 O (~99.76%) 17 O (0.04%) 18 O (0.20%) 12 C (~98.9%) 13 C (~1.1%) 35 Cl (75.77%) and 37 Cl (24.23%) 35.4527 79 Br (50.50%) and 81 Br (49.50%) 79.904. 12.0107 Amu. High Resolution MS.
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mass spectrometry II FOS 6355 Summer 2005 Russell Rouseff
Isotope Abundances • 16O (~99.76%) • 17O (0.04%) • 18O (0.20%) • 12C (~98.9%) • 13C (~1.1%) • 35Cl (75.77%) and 37Cl (24.23%) 35.4527 • 79Br (50.50%) and 81Br (49.50%) 79.904 12.0107 Amu
High Resolution MS Molecular ion M+ = 84.0937 C6H12 Possible compounds ?? C5H8O Establishes molecular formula of unknown
IR-MS • Mass spectrometry is also used to determine the isotopic composition of elements within a sample. Differences in mass among isotopes of an element are very small, and the less abundant isotopes of an element are typically very rare, so a very sensitive instrument is required. These instruments are called isotope ratio mass spectrometers (IR-MS) and use a single magnet to bend a beam of ionized particles towards a series of cups which convert particle impacts to electric current.
Menthol Peppermint Oil
Ion Trap Limitations • Requires careful quantitation • Limited dynamic range • Subject to space charge effects and ion molecule reactions • No sensitivity gain using SIM
Unpasteurized NFC GFJ TIC Intensity 20.5 20.6 20.7 20.8 20.9 21 21.1 21.2 21.3 21.4 21.5 Retention Time (min)
Unpasteurized NFC GFJ TIC Isopropyl Hexanoate o Allo-Ocimene o Intensity 20.5 20.6 20.7 20.8 20.9 21 21.1 21.2 21.3 21.4 21.5 Retention Time (min)
Linear Alkanes • Loss CH3 first - 15 • Then ethene groups – C2H4 (28) or methlene CH2 (14) • branched alkanes from more stable carbocations
Esters, Acids and Amides • Loss of group attached to carbonyl, X group • forms substituted oxonium ion From carboxylic acids From unsubstituted amides
Alcohols • Lose hydrogen and hydroxyl radical • Also lose a-alkyl (or H) groups, forms oxonium ions R1 and R2 in a position
Aromatic Hydrocarbons • forms “aromatic cluster”, m+, m-1, m/e = 65 • benzyl carbocation forms tropylium ion, then loss of acetylene = m/e 65 benzyl carbocation
Aldehydes and Ketones • Major cleavage – loss of one side chain (ketones) • generates substituted oxonium ion • McLafferty rearrangement • loss of neutral ethene – C2H4
Ethers • Lose methyl group – CH3 M-15 • forms substituted oxonium ion
Halides • Simple loss of halogen • molecular ions of Cl and Br show “halide pair” • 35Cl/37Cl ratio is roughly 3.08:1 • 79Br/81Br ratio is 1.02:1
64 100 28 29 27 50 66 26 49 51 63 65 35 48 61 30 50 37 59 67 32 41 39 44 52 0 20 24 28 32 36 40 44 48 52 56 60 64 68 Ethyl Chloride Unknown Halide Spectrum
Unknown Formula = C5H12O
Examples • Vanilla comparison • Identification of rose oil volatiles