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Stoichiometry Part II

Stoichiometry Part II. Converting Past Mole-Mole. Many stoichiometry problems follow a pattern: grams(x)  moles(x)  moles(y)  grams(y). We can start anywhere along this path depending on the question we want to answer.

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Stoichiometry Part II

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  1. StoichiometryPart II

  2. Converting Past Mole-Mole • Many stoichiometry problems follow a pattern: grams(x)  moles(x)  moles(y) grams(y) • We can start anywhere along this path depending on the question we want to answer • Notice that we cannot directly convert from grams of one compound to grams of another. Instead we have to go through moles.

  3. Molar mass of x Molar mass of y Mole ratio from balanced equation Moving along the stoichiometry path • We always use the same type of information to make the jumps between steps: grams (x)  moles (x)  moles (y)  grams (y)

  4. 59 g H2O = 6 mol H2O 18.02 g H2O 4 mol NH3 1 mol H2O Stoichiometry Question (3) 4NH3 + 5O2 6H2O + 4NO • How many grams of H2O are produced if 2.2 mol of NH3 are combined with excess oxygen? # g H2O= 2.2 mol NH3

  5. 5 mol O2 32 g O2 = 8 g O2 6 mol H2O 1 mol O2 Stoichiometry Question (4) 4NH3 + 5O2 6H2O + 4NO • How many grams of O2 are required to produce 0.3 mol of H2O? # g O2= 0.3 mol H2O

  6. 4 mol NO 30.01 g NO 1 mol O2 x x x 5 mol O2 1 mol NO 32 g O2 = 9.0 g NO Stoichiometry Question (5) 4NH3 + 5O2 6H2O + 4NO • How many grams of NO is produced if 12 g of O2 is combined with excess ammonia? # g NO= 12 g O2

  7. Have we learned it yet? Try these on your own: Given: 4NH3 + 5O2 6H2O + 4NO b) what mass of NH3 is needed to make 0.75 mol NO? c) how many grams of NO can be made from 47 g of NH3?

  8. 4 mol NO 1 mol NH3 4 mol NH3 30.01 g NO 17.04 g NH3 13 g NH3 x x x x x = 4 mol NO 1 mol NO 1 mol NH3 17.04gNH3 4 mol NH3 = 83 g NO Answers 4NH3 + 5O2 6H2O + 4NO b) c) # g NH3= 0.75 mol NO # g NO= 47 g NH3

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