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Stress Analysis of a Tower. F 0. The Method of Joints. A. B. C. Joint B. F 0. E. F. D. F AB. F CB. +Y. +X. G. H. I. F DB. F FB. F EB. A Free Body Diagram. K. L. J. M. N. O. F R. Joint B. X Forces. F 0. +F AB -F CB +F DBX -F FBX. = 0. F AB. F CB. Y Forces.
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F0 The Method of Joints A B C Joint B F0 E F D FAB FCB +Y +X G H I FDB FFB FEB A Free Body Diagram K L J M N O FR
Joint B X Forces F0 +FAB -FCB +FDBX -FFBX = 0 FAB FCB Y Forces FDB FDBY -F0 +FEB +FDBY +FFBY FDB FFB FDBX FEB +Y = 0 +X
F0 15 Joints A B C 15 FX equations 15 FY equations E F D 30 Variables G H I A “system of equations” K L J Solution would required computer software M N O FR
Yield Strength The amount of stress a material can withstand before it begins to deform Values can differ for tension or compression Use the internet to find a value for the yield strength of balsa wood in compression
Cross Sectional Area Depth = 3mm Width = 4mm 12mm2 Area = 4mm * 3mm = ?
Maximum Force P = F / A Stress = Pressure = Force / Area Stress = Yield Strength Yield Strength * Area = Max Force
Total Force Our ‘max force’ only accounts for a single truss Must count all the trusses at a given height to get total force 1 2 3 4 5 1 2 3 Sided Tower 3 Total Force = Max Force * ? 5 * 3
Reasons our predictions may be off We only accounted for forces in the Y direction Considered trusses to only experience compression Calculations did not account for imperfect craftsmanship