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Tutorial for CIVL252 Hydraulics

Tutorial for CIVL252 Hydraulics. By DUAN Huanfeng ceduan@ust.hk. y0. y1. Example 1. Problem rectangular channel with 6ft width. y0, y1 are 65ft and 1ft, respectively horsepower lost =? in the hydraulic jump. Solution From section 0 to 1 From section 1 to 2 Head loss (Method 1).

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Tutorial for CIVL252 Hydraulics

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  1. Tutorial for CIVL252 Hydraulics By DUAN Huanfeng ceduan@ust.hk

  2. y0 y1 Example 1 • Problem • rectangular channel with 6ft width. • y0, y1 are 65ft and 1ft, respectively • horsepower lost =? in the hydraulic jump

  3. Solution • From section 0 to 1 • From section 1 to 2 • Head loss (Method 1)

  4. head loss (Method 2) • For section 1 and 2: • V1=64.2ft/s; y1=1ft; • V2=?; y2=15.5ft; • According to continuity EQ: • V2=64.2*1/15.5=4.142ft/s • According to Energy EQ: • HL = (y1+V12/2g) - (y2+V22/2g)=49.2ft

  5. q=12 cfs/(s*ft) 2 1 Rectangular weir Slope = 0.04 3ft Example 2 • Problem • Water flows at a steady rate of 12 cfs per foot of width in the wide rectangular concrete channel shown. Pls determine the water surface profile from section 1 to section 2.

  6. Solution • First, determine type of the flow regime. Assume n =0.015; the depth is h1.

  7. Second, determine whether a water jump occurs upstream of the weir.

  8. Furthermore, determine the distance from the weir to where the hydraulic jump occurs.

  9. 0.74ft 3.13ft 5.26ft 57.0ft • Complete the water surface profile

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