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Balancing Redox ½ Reaction (Basic)

Balancing Redox ½ Reaction (Basic). Balancing Basic. Balancing in basic solution is just like acidic with one additional step When balancing in acidic you will have H + at the end In basic you don’t want H + , you want OH -. To change to basic.

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Balancing Redox ½ Reaction (Basic)

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  1. Balancing Redox ½ Reaction (Basic)

  2. Balancing Basic • Balancing in basic solution is just like acidic with one additional step • When balancing in acidic you will have H+ at the end • In basic you don’t want H+, you want OH-

  3. To change to basic • To change to basic, simply add an equivalent number of OH- to each side and simplify

  4. Example • Balancing the following by using the ½ reaction method in a basic solution • AsO4-3 + Zn  H3As + Zn +2 • Acidic: • 11H+ + AsO4-3 + 4Zn  H3As + 4 H2O + 4Zn+2 • Basic: • 11H+ + AsO4-3 + 4Zn  H3As + 4 H2O + 4Zn+2 • +11 OH- + 11OH- • 11 H2O + AsO4-3 + 4Zn  H3As + 4 H2O + 4Zn+2+ 11OH- • 7 H2O + AsO4-3 + 4Zn  H3As + 4Zn+2+ 11OH-

  5. Another Example • Ag + NO3- Ag + + N+2 • Acidic: • 3Ag +6 H+ + NO3- 3Ag + + N+2+ 3H2O • Basic: • 3Ag +6 H+ + NO3- 3Ag + + N+2+ 3H2O • + 6OH- + 6OH- • 3Ag +6H2O + NO3- 3Ag + + N+2+ 3H2O + 6OH- • 3Ag +3H2O + NO3- 3Ag + + N+2 + 6OH-

  6. One More • Mn(NO3)2 + NaBiO3 + HNO3 NaMnO4 + Bi(NO3)3 + H2O + NaNO3 • Acidic: • 2Mn+2 + 14H+ + 5 BiO3- 2MnO4- + 5Bi +3 + 7H2O • Basic: • 2Mn+2 + 14H+ + 5 BiO3- 2MnO4- + 5Bi +3 + 7H2O • + 14 OH- + 14 OH- • 2Mn+2 + 14H2O + 5 BiO3- 2MnO4- + 5Bi +3 + 7H2O+ 14 OH- • 2Mn+2 + 7H2O + 5 BiO3- 2MnO4- + 5Bi +3 + 14 OH-

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