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Discussion of the experiment. Weifeng Su 04/10/2009. I 1. I 3. I G. I 2. I 4. Wheatstone bridge. Principle : R A & R B are connected in series. R X & R S are connected in series. R A & R X are connected in parallel. R B & R S are connected in parallel .
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Discussion of the experiment Weifeng Su 04/10/2009
I1 I3 IG I2 I4 Wheatstone bridge Principle: • RA & RB are connected in series. RX & RS are connected in series. RA & RX are connected in parallel. RB & RS are connected in parallel. • When bridge is balanced, 1) IG=0, I1=I3 and I2=I4 2)potential of point ‘2’ = potential of point ‘4’, U2=U4 So, I1RA=I2Rx (1) I3RB=I4Rs (2) (1)/(2), Fig. 1The circuit diagram of a Wheatsone bridge
G Wheatstone bridge • Set up the circuit S2 • Balancing the bridge coarse adjustment & finer adjustment How can we get the largest sensitivity? S1 E Determine the measurement uncertainty of RX when the sensitivity M is the largest.
Oscilloscope • Principle:
Oscilloscope • Principle:
http://chem.ch.huji.ac.il/instruments/test/oscilloscope_principle_animated.htmlhttp://chem.ch.huji.ac.il/instruments/test/oscilloscope_principle_animated.html
Oscilloscope • Lissajous figure Lissajous Figures are a special case of parametric equations, where x and y are in the following form: x =A sin(at + δ) y =B sin(bt + γ) Lissajous curves can be seen on oscilloscopes and are the result of combining 2 trigonometric curves at right angles. • http://pagesperso-orange.fr/olivier.granier/meca/simul/lisajou/simul.html
Oscilloscope • How to measure a signal by oscilloscope? To measure a DC signal 0.5V/DIV 2.68DIV×0.5V/DIV=1.34V
Oscilloscope • How to measure a signal by oscilloscope? To measure an AC signal 0.5V/DIV 2ms/DIV Peak-peak amplitude:3.56DIV×0.5V/DIV=1.78V Period: T=3.16DIV×2ms/DIV=6.32ms;Frequency:f=1/T=158Hz
Input signal Input signal Output signal Output signal The property of diode to allow an electric current in one direction full-wave rectification half wave rectification