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So far, I have derived A N by assuming (Pb+Py)=1.2 for all runs.

So far, I have derived A N by assuming (Pb+Py)=1.2 for all runs. Now, I put in measured polarizations for each store from: http://www4.rcf.bnl.gov/~cnipol/pubdocs/Run09Offline/ I divide the asymmetry in each  bin by (Pb+Py), ie. /(Pb+Py) ~ A N  cos() Dealt with the errors accordingly

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So far, I have derived A N by assuming (Pb+Py)=1.2 for all runs.

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  1. So far, I have derived AN by assuming (Pb+Py)=1.2 for all runs.

  2. Now, I put in measured polarizations for each store from: http://www4.rcf.bnl.gov/~cnipol/pubdocs/Run09Offline/ • I divide the asymmetry in each  bin by (Pb+Py), ie. /(Pb+Py) ~ AN  cos() • Dealt with the errors accordingly • I didn’t include global error of polarization of 4.7% …not sure … but (Pb+Py)/(Pb+Py) is typically considerably smaller than /

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