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Ideal Gas Law

Ideal Gas Law. PV = k 1 V = k 2 T V = k 3 n PV = (k 1 k 2 k 3 )nT PV = nRT. Ideal Gas Constant. Example How many moles of gas would be in a 500. mL bottle at 2.3 atm and 295 K? PV=nRT (2.3 atm)(0.500 L) = n(0.0821 )(295 K) n = 0.047 mol.

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Ideal Gas Law

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  1. Ideal Gas Law • PV = k1 • V = k2T • V = k3n • PV = (k1k2k3)nT PV = nRT Ideal Gas Constant

  2. Example How many moles of gas would be in a 500. mL bottle at 2.3 atm and 295 K? PV=nRT (2.3 atm)(0.500 L) = n(0.0821 )(295 K) n = 0.047 mol

  3. What volume does 4.24 g of nitrogen gas occupy at 58.2oC and 2.04 atm? 58.2oC + 273.15 = 331.4 K PV=nRT (2.04 atm)V=(0.151 mol)(0.0821 )(331.4 K) V = 2.01 L

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