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Heteronuclear Practice

CN -. CN. Heteronuclear Practice. C. N. C. N. 2p. 2p. E. E. s 2s 2 s 2s *2 p 2p 4 s 2p 1. s 2s 2 s 2s *2 p 2p 4 s 2p 2. diamagnetic. p aramagnetic. Iclicker : I think I got it I need more time I’m lost. Bond order= ½ (8-2)= 3. Bond order= ½ (7-2)=2.5.

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Heteronuclear Practice

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  1. CN- CN Heteronuclear Practice C N C N 2p 2p E E s2s2s2s*2p2p4s2p1 s2s2s2s*2p2p4s2p2 diamagnetic paramagnetic Iclicker: I think I got it I need more time I’m lost Bond order= ½ (8-2)=3 Bond order= ½ (7-2)=2.5 For CN the energy of the molecular orbitals follows the order of carbon (a.k.a. p2p<s2p) Draw the MO diagram. Give the valence shell electron configurations of CN and CN-. Are they paramagnetic or diamagnetic? Tell the bond order of each. Which has the stronger bond? Stronger!

  2. Practice Iclicker: I think I got it I need more time I’m lost Maximum bond order if you remove electron from antibonding orbital. Gives +1 ion He He H H HeH +1 B.O.= ½ (2)=1 HeH Neutral B.O.= ½(2-1)=0.5 Neutral: If charge was increased: remove from antibondinggiving higher bond order. If charge decreased: add electron to antibonding giving lower bond order. +1: If charge was increased: remove from bonding giving lower bond order. If charge decreased: add electron to antibonding giving lower bond order. • Consider the hypothetical species HeH. What charge, if any, should be present on this combination of atoms to produce the most stable molecule or ion possible? • Draw the MO diagram for the neutral species first. • Decide what ion gives largest bond order • What is the bond order on the neutral species and what bond order, if changed, is on the ion you chose? • If the charge on the neutral species were increased or decreased by one what would be the affect on the bonding of the atom. • If the charge on the species you chose were increased or decreased by one what would be the affect on the bonding of the atom.

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