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Warm-up: one red book per table Page 45 Read Figure 3-5 compare to Figure 3-6 page 46

Warm-up: one red book per table Page 45 Read Figure 3-5 compare to Figure 3-6 page 46. 3.1 Section Review # 1-3 for a stamp. Warm-up: Graph the acceleration and determine if it is speeding up or slowing down (deceleration) or constant (straight line). Stamped.

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Warm-up: one red book per table Page 45 Read Figure 3-5 compare to Figure 3-6 page 46

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  1. Warm-up: one red book per table Page 45 Read Figure 3-5 compare to Figure 3-6 page 46

  2. 3.1 Section Review # 1-3 for a stamp

  3. Warm-up: Graph the acceleration and determine if it is speeding up or slowing down (deceleration) or constant (straight line). Stamped. Graph 1: Graph 2: The object dropped from The bug moved 6m at 1 s to 2m at 3s 5m at 2 s to 5m at 6s 4m at 3s to 9m at 9s 3m at 5s to 2m at 8s

  4. The distance between each dot represents the body’s change in position during that time interval. Large distances between adjacent dots indicate that the body was moving fast during that time interval. Small distances between adjacent dots indicate that the body was moving slow during that time interval. A constant distance between dots indicates that the body is moving with constant velocity and not accelerating.

  5. d = vi (t) + .5 (a)(t2) Vavg = d t Vf 2 = vi 2 + 2 (a)(d) Vf = vi + a (t) a = Δv Δt d = vi + vf 2t when vi is not 0 when vi is 0 vf = vi + g ∆t vf = g ∆t vf2 = vi2 + 2 g d vf2 = 2 g d d = vi ∆t + 0.5 g ∆t2 d = 0.5 g ∆t2 d = ( vi + vf ) ∆t d = ( vf ) ∆t 2 2

  6. A fast sprinter can cover 100m in 10s flat. • (a). What is the average speed of the sprinter? • Vavg = d100 • t 10 = 10 m/s • (b) What would his time be for the mile (1610m) • If he could keep up the sprint pace? • Vavg = d t = d1610m • t v 10m/s

  7. 2. An object moves with a constant velocity of • 15m/s. • How far will it travel in 2.0s? • Vavg = dd = v (t) • t d = 15m/s (2.0s) • d = 30m • (b) If the time is doubled, how far will it travel? • d = 15m/s(4.0s) • d = 60m

  8. 3. An object initially at rest, moves with a constant • acceleration of 10m/s2.How far will it travel in • 2.0s • d = vi (t) + .5 (a) (t2) • d = 0(2) + .5 (10) (22) • 0 + .5 (40) • 0 + 20 • d = 20m

  9. 3. An object initially at rest, moves with a constant acceleration of 10m/s2. How far will it travel in (b) 4.0s • d = vi (t) + .5 (a)(t2) • 0 (4) + .5 (10m/s2) (16) • 0 + .5 (160) • d = 80m • If the vi is 4m/s for 2 seconds(d) 4.0 seconds • d = 4m/s (2s) + .5 (10m/s2) (4s) d = 4(4) + .5 (10)(16) • 8 + .5 (40) 16 + 80 • d = 28m d = 96 m

  10. 4. A pitcher throws a baseball with a velocity of 132 ft/s (90mph) toward home plate that is approximately 60 ft away. Assuming the horizontal velocity of the ball remains constant, how long does it take to reach the plate? Vavg = d t = d 0.45s = 60 t v 132

  11. The speed of light is 3.0 x 108 m/s. Assume that • the length of a “standard room” is 20m (22 yards). • How many “room lengths” can light travel in 6.5s? • Vavg = d d = 3.0 x 108 (6.5s) d = 1.95 x 109m • t 20m • 1.95 x 109m • 20m = 9.75 x 107 room length

  12. A bunny rabbit on a jet ski increases its speed • from 25m/s to 35 m/s in a distance of 250m. • Find the time required and the acceleration. • Vavg = d t = d 8.3s = 250 m • t v 30 m/s • a = ∆v10 m/s a = 1.2 ms2 • ∆t 8.3 s

  13. 8. A reindeer running increases its velocity uniformly from 16m/s to 32m/s in 10 sec. What is its acceleration? a = ∆v16m/s = 1.6m/s2 ∆t 10s Vavg = vi + vf 16 + 32 Vavg = 24m/s 2 2 d = vi (t) + .5 (a) (t2) 16 (10) + .5 (1.6) (100) 160 + .5 (160) d = 240m

  14. Free fall • A ball is thrown straight up in the air. • The moment it leaves the hand of the person • throwing it, it accelerates at a rate of -9.8 m/s2. • If the ball travels 19.2 m up, then what was its initial velocity? • 2. How long does it take to reach the top of its • trajectory? (19.2 m)

  15. Givens: formula: d = 19.2m vf = vi2 + 2ad vf = 0 0 = vi 2 + 2(-9.8)(19.2) a = 9.8m/s2 0 = vi2 + (-376.32) Vi? How do we isolate vi2? vi2 = √376.32

  16. Givens: formula: d-=19.2 m vf = vi + a(t) vf = 0 m/s 0 = 19.40 + (-9.8)t vi = 19.40 m/s -19.40 = -19.40 a = 9.8 m/s2 - 19.40 = -9.8(t) How do we isolate time? t = 1.98s

  17. Page 6 in blue book A common flea can jump a distance of 33 cm. Suppose a flea makes five jumps of this length in the northwest direction. If the flea’s northward displacement is 88 cm, what is the flea’s westward displacement? Scale 1cm = 33cm Vector is pointing north of west What is one half of 90°?

  18. The longest snake ever found was a python 10.0 m long. If the snake were stretched along a coordinate system on the ground from the origin making a 60° angle with the positive x-axis. Find the x and y coordinates of the vector the snake makes.

  19. A South-African sharp-nosed frog set a record for a triple jump by traveling a distance of 10.3 m. Suppose the frog starts from the origin of a coordinate system and lands at -6.10 m relative to the y-axis, what angle does the vector of displacement (frog’s leap) make with the y-axis? And what is the x-component of the frog’s leap?

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