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Bell Work

Bell Work. Find the area of each figure. 22 in. 9 in. 5 in. 6 in. 10 in. 13 in. 16 in. A = (13 + 9 ) • 5. A = (16 + 22) • 10. A = (22) • 5. A = (38) • 10. A = 11• 5. A = 19 • 10. A = 55 in². A = 190 in². Area of a Trapezoid. Area of Trapezoid.

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Bell Work

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  1. Bell Work Find the area of each figure. 22 in 9 in 5in 6 in 10 in 13 in 16 in A = (13 + 9) • 5 A = (16 + 22) • 10 A = (22) • 5 A = (38) • 10 A = 11• 5 A = 19 • 10 A = 55 in² A = 190 in²

  2. Area of a Trapezoid Area of Trapezoid 6 in 5in A = (b1 + b2) •h 5 in 2 in 8 in A = (6 + 8) •2 Perimeter of Trapezoid A = (14) •2 P= 5 + 5 + 8 + 6 A = 7•2 P= 24 in A = 14 in²

  3. Missing lengths of Parallelograms and Triangles

  4. Formulas Area of Parallelogram = Base x Height A = bh Remember: The height is the line segment that is perpendicular to the base and creates a right angle. Area of Triangle = (Base x Height) A = bh Remember: A triangle is HALF of a parallelogram.

  5. Example • Find the height of the parallelogram when the area is 252 in² and the base is 36in. A=bh 252 =36h h = 7 in 7 in 36 36 36 in

  6. A treadmill’s belt is in the shape of a parallelogram before the ends are joined to form a loop. The area of the belt is 2052 in². The belt’s width, which is the height of the parallelogram, is 18 inches. Find the length of the belt, which is the base of the parallelogram.

  7. 18 in b A=bh 2052= b(18) b =114 The length of the treadmill’s belt is 114 inches

  8. Example A = bh 2400 = b(50) 2400 = 25b b = 96 ft Find the base of the triangle when the area is 2400 ft². 50 ft 25 25

  9. Finding the Base of a Triangle A = bh 35= b(10) 35 = 5b b = 7 cm 5 5 • A triangle has a height of 10 centimeters and an area of 35 square centimeters. Find the base of the triangle. • Write the formula for area of a triangle. • Substitute in values. • Simplify. • Solve.

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