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F = mg Sin q

q. L. therefore, the arc distance is within 1% of the straight distance (dottted line) (see next page). T. x. mg Cos q. mg Sin q. mg. T= 2 p m/k. From SHM. T = 2 p m mg/L. = 2 p L/g. f = 1 g/L 2 p. F = mg Sin q.

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F = mg Sin q

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  1. q L therefore, the arc distance is within 1% of the straight distance (dottted line) (see next page) T x mg Cos q mg Sin q mg T= 2p m/k From SHM T = 2p m mg/L = 2p L/g f = 1 g/L 2p F = mg Sin q for @5o of arc Sin q =.087 F = mg Sinq = mg q Sin q = x/L x = Sin q L Sin q = q x = q L q = x/L F = mg(x/L) or, F = (mg/L)x F = kx k = mg/L

  2. q Pendulum with 5o arc or less L = 1.0 m Trig. Functions for triangles Rotational formulas for circles L q q 5o (1 rad/57.3O) = .0873 rad L L x x Sin 5o = x/1.0 m x = Sin 5o(1.0 m) x = .0872 m q = x/L x = .0873 rad(1.0 m) x = .0873 m

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