170 likes | 364 Views
Unit: Radical Functions 7-5: Solving Radical Equations. Essential Question: Describe the procedure for solving a radical equation. 7-5: Solving Radical Equations. A radical equation is an equation that has a variable in a radicand or a variable with a rational exponent. radical equation
E N D
Unit: Radical Functions7-5: Solving Radical Equations Essential Question: Describe the procedure for solving a radical equation
7-5: Solving Radical Equations • A radical equation is an equation that has a variable in a radicand or a variable with a rational exponent. • radical equation • radical equation • not a radical equation • To solve a radical equation, isolate the radical on one side of the equation and then raise both sides of the equation to the inverse power.
7-5: Solving Radical Equations • Example: • Goal is to get by itself • Subtract 2 from both sides • Inverse of square root? • Square each side • Add 2 to both sides • Divide both sides by 3
7-5: Solving Radical Equations • Your Turn
7-5: Solving Radical Equations • Example: • Goal is to get by itself • Divide both sides by 2 • Inverse of 2/3 power? • Take each side to 3/2 power Use absolute values only when taking an even root • Make two equations • Add 2 to both sides
7-5: Solving Radical Equations • Example:
7-5: Solving Radical Equations • Assignment • Page 394 • 1 – 12 • All problems • Show work
Unit: Radical Functions7-5: Solving Radical EquationsDay 2 Essential Question: Describe the procedure for solving a radical equation
7-5: Solving Radical Equations • Much like with absolute value equations, you’ll have to check for extraneous solutions. • Part 1 – Solving the problem • Get by itself • Subtract 5, both sides • Square both sides • FOIL right side • Subtract x & add 3 • Factor • Solve each parenthesis
7-5: Solving Radical Equations • Part 2 – Checking for extraneous solutions • Original Problem • Two solutions • The only solution is x = 7
7-5: Solving Radical Equations • Your Turn
7-5: Solving Radical Equations • Part 2 – Checking for extraneous solutions • Original Problem • Two solutions Real Solution Extraneous Solution The only solution is x = 10
7-5: Solving Radical Equations • Get the two equations on opposite sides • Raise both sides to eliminate the smallest power • FOIL the left side Get equation = 0 • Subtract 3x on both sides Subtract 4 on both sides • Factor the equation • Solve each parenthesis
7-5: Solving Radical Equations • Part 2 – Checking for extraneous solutions • Original Problem • Two solutions • Let’s check x = -1
7-5: Solving Radical Equations • Part 2 – Checking for extraneous solutions • Original Problem • Two solutions • ¾ is the only real solution (-1)0.5 is not a real number
7-5: Solving Radical Equations • Your Turn
7-5: Solving Radical Equations • Assignment • Page 394 - 395 • 15 – 29 • Odd problems • Show work • Note: All problems have at least one real solution. Some will also have one extraneous solution & the book will not give you the extraneous solution, but I want both.