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Unit 5 Part 1. Perpendicular Bisector, Median and Altitude of Triangles. Midpoint of a segment. Perpendicular Bisector. Any point on the perpendicular bisector of a line segment is equidistance from the endpoints of the segment. Perpendicular Bisector of a Triangle.
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Unit 5 Part 1 Perpendicular Bisector, Median and Altitude of Triangles
Perpendicular Bisector • Any point on the perpendicular bisector of a line segment is equidistance from the endpoints of the segment.
Perpendicular Bisector of a Triangle. • The perpendicular bisector of a triangle is formed by constructing perpendicular bisectors of each side of the triangle. • GeoGebra File Perpendicular bisector Circumscribed circle
Median of a Triangle • The median of a triangle is the line segment from a vertex to the midpoint of the opposite side of that vertex. • GeoGebra File
Altitude of a Triangle Altitude also known as the height.
Angle Bisector • Any point on the angle bisector is equidistance from the sides of the angle.
Solve for ‘x’. 3x – 10 = 2x +18 - 2x - 2x 3x – 10 x – 10 = 18 +10 + 10 x = 28 x 2x + 18
Angle bisector of a triangle. • GeoGebra File Angle bisector Inscribed circle
Draw • AB is a median of ∆BOC • RA is the altitude and median of ∆RST • AE and CD are ∠ bisectors of ∆ACB and intersect at “x”. • FS and AV are altitudes of ∆FAT and intersect outside the triangle.
Altitude Median • SM is an _______________ of ∆RSE. • If SN = NE, then RN is a _____________ of ∆RSE. • If ∠SNL is congruent to ∠LER, then LE is an ____________________ of ∆RSE. • SN = NE, therefore NT is a ___________________ of ∆RSE Angle Bisector Perpendicular Bisector S N L E M R T