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Drill: Calculate the pH of 2.0 x 10 -4 M HI. Calculate the pH of 3.3 x 10 -8 M HI. Acid-Base Equilibria. Ionization of Water. H 2 O (l) H + (aq) + OH - (aq) 2 H 2 O (l) H 3 O + (aq) + OH - (aq). Water Ionization Constant. K w = [H + ][OH - ] K w = [H 3 O + ][OH - ]
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Ionization of Water H2O(l) H+(aq)+ OH-(aq) 2 H2O(l) H3O+(aq) + OH-(aq)
Water Ionization Constant Kw = [H+][OH-] Kw = [H3O+][OH-] Kw = 1.00 x 10-14 Memorize this
Kw Calculations In pure water [H+] = [OH-] Kw =[H+][OH-] = 1.0 x 10-14 Let [H+] = x = [OH-]
Kw Calculations Kw =[H+][OH-] = x2 Kw = x2 =1.0 x 10-14 Thus x = 1.0 x 10-7 M [H+] = x = 1.0 x 10-7 M
pH of Pure Water [H+] = 1.0 x 10-7 M pH = -log[H+] pH = -log[1.0 x 10-7] pH = 7 -log 1 Thus pH = 7.00
AP CHM HW • Problems: 9 • Page: 395
CHM II HW • Problems: 27 • Page: 787
Weak Acid Ionization HA(aq) H+(aq) + A-(aq) HA(aq) + H2O(l) H3O+(aq) + A-(aq)
Acid Dissociation Constant HA(aq)H+(aq) + A-(aq) • [H+][A-] • [HA] Ka =
Weak Base Ionization NH3(aq) + H2O(l) NH4+(aq) + OH-(aq)
Base Dissociation Constant NH3(aq) + H2O(l) NH4+(aq) + OH-(aq) • [NH4+][OH-] • [NH3] Kb =
Calculate [H+], [OH-], pH, & pOH of 2.0 M HC2H3O2 (HAc)Ka = 1.8 x 10-5
Drill: Calculate [H+], [OH-], pH, & pOH of0.50 M NH3Kb = 1.8 x 10-5
Calculate [H+],[OH-], pH, & pOH of 0.010 M HC7H5O2 (HBz)Ka = 6.4 x 10-5
AP CHM HW • Problems: 37 • Page: 396
CHM II HW • Problems: 43 • Page: 788
Drill: Calculate [H+], [OH-], pH, & pOH of 0.50 M C6H5NH2Kb = 3.2 x 10-5
Calculate the Ka of 0.10 M Hquack when it ionized 5.0 % in an aqueous solution.
Drill: The pH of a 0.79 M solution of Hnut is 3.10. Calculate its Ka
Calculate the pH of a solution of 0.00050 M HBS : Ka = 5.0 x 10-12
AP CHM HW • Problems: 39 • Page: 397
CHM II HW • Problems: 45 • Page: 788
Calculate [H2CO3], [HCO3-], [CO3-2], [H+],[OH-], & pH of 0.44 M H2CO3Ka1 = 4.4 x 10-7Ka2 = 4.7 x 10-11
AP CHM Test covering A/B & A/B Equilibria will be on Thursday
CHM II Test covering A/B & A/B Equilibria will be on Thursday
Calculate [H2SeO3], [HSeO3-], [SeO3-2], [H+],[OH-], & pH of 0.27 M H2SeO3Ka1 = 2.7 x 10-7Ka2 = 5.4 x 10-11
AP CHM HW • Problem 39 on page 396
Calculate [H3A],[H2A-], [HA-2],[A-3],[H+], &pH of 0.30 M H3A Ka1 = 3.0 x 10-7Ka2 = 5.0 x 10-11Ka3 = 4.0 x 10-15
AP CHM HW • Work problem 55 on page 397 • Test Thursday
CHM II HW • Work problem 53 on page 788 • Test Thursday
Be able to name: • Acids • Bases
Be able to describe & Identify: • Strong Acids • Strong Bases
Drill: Calculate the pH, & pOH of 0.10 M HNO2Ka = 6.0 x 10-4