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Predicting Products in Reactions

Predicting Products in Reactions. Recall: The 5 Types of Reactions A + B  AB – Formation AB  A + B – Decomposition A + BC  B + AC – Single Replacement AB + CD  AD + CD – Double Replacement C X H Y + O 2  CO 2 + H 2 O – Hydrocarbon combustion. Formations:. Examples:.

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Predicting Products in Reactions

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  1. Predicting Products in Reactions Recall: The 5 Types of Reactions • A + B  AB – Formation • AB  A + B – Decomposition • A + BC  B + AC – Single Replacement • AB + CD  AD + CD – Double Replacement • CXHY + O2  CO2 + H2O – Hydrocarbon combustion

  2. Formations:

  3. Examples: Na(s) + Cl2(g)  S8(s) + Al(s)  Cr(s) + N2(g)  K(s) + P4(s)

  4. Answers: 2Na(s) + Cl2(g)  2NaCl(s) 3S8(s) + 16Al(s)  8Al2S3(s) 2Cr(s) + N2(g)  2CrN(s) 12K(s) + P4(s)  4K3P(s)

  5. Decomposition: AlBr3(s)  Rb3N(s)  CuCl2(s)  P2F8(g)

  6. Answers: 2AlBr3(s)  2Al(s) + 3Br2(l) 2Rb3N(s)  6Rb(s) + N2(g) CuCl2(s)  Cu(s) + Cl2(g) 2P2F8(g)  P4(s) + 8F2(g)

  7. Single Replacement: Sc(s) + NaCl(s)  Al(NO3)3(s) + Mg(s)  Br2(l) CaF2(s)  Sr3N2(s) + P4(s) 

  8. Answers: Sc(s) + 3NaCl(s)  ScCl3(s) + Na(s) 2Al(NO3)3(s) + 3Mg(s)  2Al(s) + 3Mg(NO3)2 Br2(l) CaF2(s)  F2(g) + CaBr2 2Sr3N2(s) + P4(s)  2Sr3P2(s) + 2N2(g)

  9. Double Replacements: SrO + AlBr3 Ba3N2 + CuS  K3PO4 + Sc2(SO4)3  (NH4)2O + Na3BO3 

  10. Answers: 3SrO + 2AlBr3 3SrBr2 + Al2O3 Ba3N2 + 3CuS  3BaS + Cu3N2 2K3PO4 + Sc2(SO4)3  3K2SO4 + 2ScPO4 3(NH4)2O + 2Na3BO3  2(NH4)3BO3 + 3Na2O

  11. Acid Base Neutralization: (an example of a Double Replacement) NaOH(aq) + HBr(aq)  H2SO4(aq) + Ca(OH)2  NH4OH(aq) + HNO2(aq) 

  12. Answers: NaOH(aq) + HBr(aq)  H2O(l) + NaBr(aq) H2SO4(aq) + Ca(OH)2  2H2O(l) + CaSO4(aq) NH4OH(aq) + HNO2(aq)  H2O(l) + NH4NO2(aq)

  13. Hydrocarbon Combustion: • http://www.youtube.com/watch?feature=player_embedded&v=7UoFNdp0UYg

  14. Hydrocarbon Combustion: CH4(g) + O2(g)  C2H6(g) + O2(g)  C3H5(g) + O2(g) 

  15. Hydrocarbon Combustion: CH4(g) + 2O2(g)  CO2(g) + 2H2O(g) 2C2H6(g) + 5O2(g)  4CO2(g) + 6H2O(g) 4C3H5(g) + 17O2(g)  12CO2(g) + 10H2O(g)

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