1 / 17

LCT 50 Formulation

Lethal Concentration Time. LCT 50 Formulation. LCT 50 Course Overview. Purpose History Philosophy: CATO vs. NTOA Formula and Calculations Practical Applications Tactical Case Study. LCT 50 Purpose. Helps determine amount of chemical agent to use.

atara
Download Presentation

LCT 50 Formulation

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Lethal Concentration Time LCT50 Formulation

  2. LCT50 Course Overview • Purpose • History • Philosophy: CATO vs. NTOA • Formula and Calculations • Practical Applications • Tactical Case Study

  3. LCT50 Purpose • Helps determine amount of chemical agent to use. • Estimates the time a suspect can remain in agent environment. • Provides a guideline for command staff and for potential criminal & civil litigation.

  4. LCT50 Defined “Concentration (LC50) multiplied by the time (T) of exposure that is lethal to 50% of exposed personnel.” (Usually expressed in minutes of exposure.)

  5. LCT50 History • Formula developed from an Edgewood Arsenal study of CS exposure in 1967. • Edgewood Arsenal is a chemical research facility (now known as US Army Medical Research Institute of Chemical Defense). • Conducted for the U.S Army who was replacing CN with CS for outside riot control. Not inside or for civil law enforcement! • Conducted in a static, sealed container. • Formula values determined concentration levels were lethal for 50% of population.

  6. LCT50 Philosophy • National Tactical Officer’s Association • California Association of Tactical Officers

  7. LCT50 Philosophy NTOA • Based on use of force “reasonableness” standard (Graham vs. Connor). • Don’t need a formula to use other forms of force. • LCT50 based on faulted research: • No consideration given to biological/metabolic differences. • Conducted in static sealed containers. • CS was intended for outside riot control, not inside sealed environments.

  8. LCT50 Philosophy CATO • Formula and incident based. • Uses Edgewood Arsenal Study as a “baseline.” • Bases concentration variable (i.e. .004, .008, etc) on tactical situation. • Estimates the time a suspect can remain in the agent.

  9. LCT50 Formula 3-Step Process • Compute room(s) volume ( L x W x H ) Equals =CUBIC FEET • CUBIC FEETX CONCENTRATION VARIABLE Equals = GRAMS of AGENT NEEDED • CUBIC FEET GRAMS of AGENT NEEDEDX .71 (CS Constant) = LCT50 in minutes

  10. LCT50 Formula (CV) Concentration Variable • Equates to grams of agent per 1000 cubic feet. • US Department of Energy research determined 4 grams per 1000 cubic feet ( or .004) as the smallest concentration to yield agent symptoms. • A higher variable will give a higher concentration of agent, but a shorter LCT50. • A lower variable will yield a lower agent concentration, but a higher LCT50. • For Example: • .012 = 60 minutes • .008 = 89 minutes • .004 = 178 minutes • Concentration variables should be based on SWAT chemical agent deployment philosophy.

  11. LCT50 Formula (Constant) Constant (.71) • Based on US Army research. • Research that was based on how much agent would kill a human. • Will never change.

  12. LCT50 Worksheet (part 1) 1._______ x _______ x _______ = ___________ Length Width Height Cubic Feet 2._________ x CV = _________________ Cubic Feet Total Grams Needed 3.__________ ________ x .71 = _____________ Cubic Feet Total # of LCT50 (minutes) Grams

  13. LCT50 Worksheet (part 2)ProposedLCT50 - Time 1._______ x _______ x _______ = ___________ Length Width Height Cubic Feet 2._________ x .71 _______________ = ________________ Cubic Feet Proposed LCT50 Grams of Agent

  14. LCT50 Worksheet (part 2)Amount of Agent Used 1._______ x _______ x _______ = ___________ Length Width Height Cubic Feet 2.__________ ______________ x .71 = _______________ Cubic Feet Grams of Agent LCT50 (minutes)

  15. LCT50 Munitions Needed Now that we know the “total # of grams of agent” and our LCT50, how many munitions will we need? ANSWER: Divide total # of grams of agent by the amount of agent in your munition of choice. This is where a munitions data card comes in handy!

  16. Munition Data Cards

  17. Questionsor Comments

More Related