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8.4 Word Problems

8.4 Word Problems. Math 9. The length of a rectangular garden is 1 m more than three times the garden’s width. If the perimeter of the garden is 34 m, find its dimensions .

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8.4 Word Problems

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  1. 8.4 Word Problems Math 9

  2. The length of a rectangular garden is 1 m more than three times the garden’s width.If the perimeter of the garden is 34 m, find its dimensions.

  3. The length of a rectangular garden is 1 m more than three times the garden’s width.If the perimeter of the garden is 34 m, find its dimensions. Let x = the width of the rectangle Let 3x + 1 = the length of the rectangle 3X + 1 X X 3X + 1

  4. Let x = the width of the rectangle Let 3x + 1 = the length of the rectangle 34/2 = 3x + 1 + x 17 = 4x + 1 -1 -1 16 = 4x ÷4 ÷4 4 = x Length of rectangle: 3x + 1 = 3(4) + 1 = 13 The width of the rectangle is 4 and the length of the rectangle is 13. X 3X + 1

  5. The cash register in the school canteen contains x quarters and (30 – x) dimes. If the total value of the coins is $5.85, how many of each kind of coin are there?

  6. The cash register in the school canteen contains x quarters and (30 – x) dimes. If the total value of the coins is $5.85, how many of each kind of coin are there? 0.25x + 0.10(30-x) = 5.85 0.25x + 3.00 - 0.10x = 5.85 0.15x + 3.00 = 5.85 - 3.00 -3.00 0.15x = 2.85 ÷0.15 ÷0.15 x = 19 Multiply 0.10 into the brackets Combine x values Get term with x by itself Isolate x

  7. The cash register in the school canteen contains x quarters and (30 – x) dimes. If the total value of the coins is $5.85, how many of each kind of coin are there? 0.25x + 0.10(30-x) = 5.85 0.25x + 3.00 - 0.10x = 5.85 0.15x + 3.00 = 5.85 - 3.00 -3.00 0.15x = 2.85 ÷0.15 ÷0.15 x = 19 Dimes = 30 – x = 30 – 19 = 11 There are 11 dimes and 19 quarters in the canteen

  8. An employee mixes peanuts worth $2.80/kg with cashews worth $3.60/kg. She sells the mixture for $3.12/kg. If she has 75 kg of peanuts, how many kilograms of cashews does she need?

  9. An employee mixes peanuts worth $2.80/kg with cashews worth $3.60/kg. She sells the mixture for $3.12/kg. If she has 75 kg of peanuts, how many kilograms of cashews does she need? Let x = the amount of peanuts in the ratio Let 1-x = the amount of cashews in the ratio 2.80x + 3.60(1-x) = 3.12 2.80x + 3.60 – 3.60x = 3.12 3.60 – 0.80x = 3.12 -3.60 -3.60 -0.80x = -0.48 ÷-0.80 ÷-0.80 X = 0.6 1- x = 0.4 75 75 kilograms of cashews are needed to create this mixture.

  10. Time, Rate and Distance 2h x 100km/h = 200 km How long does it take to travel 900 km at 75 km/h? 900 ÷ 75 = 12 What is the rate if you travel 150 km in 3 h?

  11. Plane A leaves the airport. One hour later, Plane B leaves the same airport on the same course. It catches up to Plane A in 2 ½ h. The average speed of Plane B is 300 km/h faster than Plane A. Find the speed of each plane.

  12. Plane A leaves the airport. One hour later, Plane B leaves the same airport on the same course. It catches up to Plane A in 2 ½ h. The average speed of Plane B is 300 km/h faster than Plane A. Find the speed of each plane. Let a = the speed of Plane A Let 300 + a = the speed of Plane B 3.5a =2.5(300+a) 3.5a = 750 + 2.5a -2.5a -2.5a a = 750 300+ a = 300 +750 =1050 Before you can answer this question you must ask your self what will be equal at the end That means Plane A is travelling at 750km/h and Plane B is travelling at 1050 km/h. Its Distance, which is calculated by multiplying speed with time

  13. That’s it for now

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