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Unit 23 Algebraic Manipulation. Unit 23 Algebraic Manipulation. 23.1 Simultaneous Linear Equations. Problem Solve the pair of simultaneous equations. Solution In order to be able to eliminate x , we multiply the first equation by 4 and the second by 3, to give.
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Unit 23Algebraic Manipulation 23.1 Simultaneous Linear Equations
Problem Solve the pair of simultaneous equations Solution In order to be able to eliminate x, we multiply the first equation by 4 and the second by 3, to give So if y = -2 we substitute back to find x, y ? ? ? ? ? Then add the equations ? ? ? ? ? ? Hence ? ?
Unit 23Algebraic Manipulation 23.2 Expanding Brackets
Expand Solution (a) (b) (d) (c) (a) ? ? ? (d) (c) (b) ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?
Unit 21Formula 23.3 Linear Factorisation
Factorise (a) (b) Solution (a) This is the reverse of the process of expanding. As 2 is a common factor of both terms, (b) The common factor of and is ? ? ? ? ? ? ? ? ?
Unit 23Algebraic Manipulation 23.4 Quadratic Factors 1
Factorise Solution This will be in the form of So If the possible values are ? ? ? Which of these values satisfies ? ? ? ? ? ? ? ? ? ? ?
Unit 23Algebraic Manipulation 23.5 Quadratic Factors 2
Factorise Solution This must be in the form So and These are the possibilities if ? ? ? Hence and ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?