11.

Sep 04, 2014

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11. z. y. o. x. 1. 1. z. y. o. x. 11. 1. S. D. 1. 12. z. 0. y. x. 设圆柱面为. 考虑第一卦限. a. a. z. y. x. o. 0. y. x. 12. 设圆柱面为. a. D. a. a. D. a. 13. z. o. y. x. a. z. o. x. y. 13. S =. 共同的 D :. D. 14. x. o. 2. z. y. x. z. y. 14. 问题：

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