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Geometric Similarities

Geometric Similarities. Math 416. Geometric Similarities Time Frame. 1) Similarity Correspondence 2) Proportionality (SSS) (Side-side-side) 3) Proportionality (SAS) (side-angle-side) 4) Similarity Postulates 5) Deductions 6) Dimensions 7) Three Dimensions. Similarity Correspondence.

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Geometric Similarities

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  1. Geometric Similarities Math 416

  2. Geometric Similarities Time Frame • 1) Similarity Correspondence • 2) Proportionality (SSS) (Side-side-side) • 3) Proportionality (SAS) (side-angle-side) • 4) Similarity Postulates • 5) Deductions • 6) Dimensions • 7) Three Dimensions

  3. Similarity Correspondence • Similarity – Two shapes are said to be similar if they have the same angles and their sides are proportional • Note – we see shape by angles & we see size with side length

  4. Consider A Similar & Why? D 8 100 95 24 16 X 5 W 100 95 10 15 85 80 80 85 B 32 C Z Y 20

  5. Proportionality (SSS) • We say the two shapes are similar because their angles are the same and their sides are proportional • We can note corresponding points • A  X • D  W • B  Y • C  Z

  6. Angles • We note corresponding angles • < ADC = < XWZ (95°) • < DCB = < WZY (85°) • < CBA = < ZYX (80°) • < BAD = < YXW (100°)

  7. Notes • Hence we would say ADCB XWZY • Hence we note corresponding angles • < ADC = < XWZ • < DCB = < WZY • < CBA = < ZYX • < BAD = < YXW

  8. Proportionality • Next is proportionality which we will state as a fraction • AD=8DC=16CB=32BA=24 XW 5 WZ 10 ZY 20 YX 15 • What is the proportion (not in a fraction)? • 8/5 which is reduced to 1.6

  9. Question #1 • Identify the similar figures and state the similarity relationship, side proportion and angle equality T A BIG MED MED B Z BIG C SMALL SMALL C

  10. Notes for Solution • By observing you need to establish the relationship. • Look at angles or side lengths • Important: An important trick when comparing angles and sides is that the biggest angles is always across the biggest side, the smallest from the smallest and medium from the medium.

  11. Solution #1 • Triangle ABC ˜ TCZ • AB = BC = CA TC CZ ZT • < ABC = < TCZ < BCA = <CZT < CAB = <ZTC

  12. Important Note • Make sure the middle angle letters are all different because the middle letter is the actual angle that you are looking at. • AC = CA • < ACB = < BCA • Both the above are the same

  13. Question #2 R K SMALL MED MED T MED L MED SMALL X Q With isosceles (or equilateral triangles) you may get two (or three) different answers). However, you are only required to provide one.

  14. Solution a for #2 • The question is to identify similar figures and state the similarity relationship, side proportion and graph equality. • QK = KT = QT RX XL RL • < QKT = < RXL < KTQ = < XLR < TQK = < LRX QKT ˜ RXL

  15. Solution b for #2 • You can also have another solution • Triangle QKT is still congruent to RLX • QK = KT = QT RL LX RX • < QKT = < RLX < KTQ = < LXR < TQK = XRL

  16. More Notes  • There are other ways of establishing similarity in triangles • At this point we will abandon reality for simple effective but not accurate drawings of triangles… (it is not to scale). • Please complete #1 a – o • For Question #3, again, state similarity relationship, side proportion and angle equality.

  17. Question #3 T A 35 45 21 18 Q B 30 R 27 C If the three sides are proportional to the corresponding three sides in the other triangle, the two will be similar.

  18. Solution Notes • You need to check… • SMALL with SMALL • MEDIUM with MEDIUM • BIG with BIG

  19. Solution #3 • ABC ˜ QRT Small Small Big Med Med Big • 18 = 21 = 27 • 35 45 • 0.6 = 0.6 = 0.6; YES SIMILAR

  20. Proportionality SAS • We can also show similarity in triangles if we can find two set corresponding sides proportional and the contained angles equal; we can determine similarity X A 15 18 14° 42 14° Y 35 Z B C

  21. Question #4 • Show if the triangle is similar • Solution… since • <BAC = <XYZ = 14° • 18 = 42 15 35 = 6/5 6/5 • BAC ˜ XYZ • Notice BAC = Small, Angle, Big & compared to Small, Angle, Big

  22. Triangle Similarity Postulates • There are three main postulates we use to state similarity • SSS all corresponding sides proportional • SAS two sets of corresponding sides and the contained angle are equal • AA two angles (the third is automatically equal since in a triangle, the interior angle must add up to 180°) are equal

  23. Example #1 • Why are the following statements true? • QPT ˜ ZXA AA X Q 84° 42° 54° 84° 54° P T A Z

  24. Example #2 • Why are the following statements true? • KTR ˜ PMN SAS M R 51° 18 16 27 51° T K N 24 P Solution: since 24/16 = 27/18

  25. Example #3 K A 16 12 6 24 B C T 9 32 P Since 16 = 24 = 32 6 9 12 8/3 = 8/3 = 8/3 S S S

  26. Parallel Lines • Facts: If two tranversals intersect three parallel lines, the segments between the lines are proportional a c b d Therefore, a = c b d

  27. Notes • Also note that… C • BC = 1 AC 2 B • A •

  28. Parallel and the Triangle • If a parallel line to a side of a triangle intersects the other two sides it creates two similar triangles A Therefore, ABE ˜ ACD B E C D

  29. Question #1 3 9 • 3 = 9 • x • 3x = 36 • x = 12 4 x Find x

  30. Question #2 A We note BE // CD Thus, ABE ˜ ACD AB = BE = AE AC CD AD x = 50 = AE x+40 150 AD x E B 50 40 C D 150

  31. Question #2 Sol’n Con’t • We only need x = 50 x+40 150 • 150x = 50(x+40) • 150x = 50x + 2000 • 100x = 2000 • x = 20

  32. Proportion Ratio • Consider 1 10 1 10

  33. Dimensions

  34. Dimensions • In general in 1D if a:b then in 2D a2 : b2 • Ex. In 1D if 5:3 then in 2D? • In 2D then 25:9 • You can go backwards by using square root • Ex. In 2D if 36:49 then in 1D • 6:7

  35. 3D or Volume • Consider 1 5 1 5 1 5

  36. 3D or Volume

  37. 3D or Volume • In general in 1D if a:b then in 3D… • Then in 3D a3 : b3 • Ex. In 1D if 6:7 then in 3D • In 3d 216:343 • You can go backwards by using the cube root • Ex. In 3D if 27:8 then in 1D • In 1D 3:2

  38. Practice Complete the following 1 D Length 2 D Area 3 D Volume 2:9 4:81 8:729 2:11 4:121 8:1331 25:9 125:27 5:3

  39. 3D Question #1 • Two spheres have a volume ratio of 64:125. If the radius of the large one is 11cm, what is the radius of the small one? • Big Small • r 11 x 3D Ratio 64:125 1D Ratio 4:5 Thus 4 = x 5 11 5x = 44 x = 8.8

  40. 3D Question #2 V = ? V=200m3 A base = 16 m2 A Base = 100m2

  41. Question #2 Solution Big Small Area of Base 100 16 Volume 200 x 1 Ratio 10 / 4 2 Ratio 100/16 3 Ratio 1000/64 Thus 200 = 1000 x 64 1000x = 12800 x = 12.8

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