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Equations Warm Up Problem of the Day Lesson Presentation

This lesson presentation includes a warm-up activity, problem of the day, and quizzes to practice solving addition, subtraction, multiplication, and division equations. It aligns with the Sunshine State Standards MA 7.A.3.3 and MA 7.A.3.4.

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Equations Warm Up Problem of the Day Lesson Presentation

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  1. Warm Up Problem of the Day Lesson Presentation Lesson Quizzes

  2. Warm Up Use mental math to find each solution. 1.7 + y = 15 2.x ÷ 9 = 9 3. 6x = 24 4.x – 12 = 30 y = 8 x = 81 x = 4 x = 42

  3. Problem of the Day Zelda sold her wet suit to a friend for $156. She sold her tank, mask, and snorkel for $85 less than she sold her wet suit. She bought a used wet suit for $80 and a used tank, mask, and snorkel for $36. If she started with $0, how much money does she have left? $111

  4. Sunshine State Standards MA.7.A.3.3 Formulate and use different strategies to solve one-step…linear equations. AlsoMA.7.A.3.4

  5. ? –6 + (–1) = –7 ? –7 = –7 Additional Example 1A: Solving Addition and Subtraction Equations Solve each question. Check each answer. –6 + x = –7 –6 + x = –7 + 6 + 6 Add 6 to both sides to isolate the variable. x = –1 Check –6 + x = –7 Substitute –1 for x. True. 

  6. ? –8 + 5 = –3 ? – 3 = –3 Additional Example 1B: Solving Addition and Subtraction Equations Solve each equation. Check each answer. p + 5 = –3 p + 5 = –3 + (–5) +(–5) Add –5 to both sides. p = –8 Check p + 5 = –3 Substitute –8 for p. True. 

  7. ? –31 – 9 = –40 ? –40 = –40 Additional Example 1C: Solving Addition and Subtraction Equations Solve each equation. Check each answer. y – 9 = –40 y – 9 = –40 + 9 + 9 Add 9 to both sides. y = –31 Check y – 9 = –40 Substitute –31 for y.  True.

  8. Check It Out: Example 1 Solve each equation. Check your answer. y – 7 = –34 A. y – 7 = –34 + 7+7 y = –27 – 7 + b = 9 B. –7 + b = 9 +7+7 b = 16

  9. Check It Out: Example 1 Solve each equation. Check each answer. m – 5 = –12 C. m – 5 = –12 +5 +5 m = –7

  10. Additional Example 2A: Solving Multiplication and Division Equations Solve each equation. Check each answer. b –5 = 6 b –5 = 6 b –5 = (–5)6 (–5) Multiply both sides by –5. b = –30

  11. Additional Example 2A Continued Check b –5 = 6 –30 ? Substitute –30 for b. = 6 – 5 True. 6 = 6  b –5 = 6.

  12. Additional Example 2B: Solving Multiplication and Division Equations Solve each equation. Check each answer. –400 = 8y –400 = 8y –400 = 8y Divide both sides by 8. 8 8 –50 = y

  13. Additional Example 2B: Solving Multiplication and Division Equations Check –400 = 8y Substitute –50 for y. ? –400 = 8(–50) True. –400 = –400 

  14. Check It Out: Example 2A Solve each equation. Check your answer. c 4 = –12 c 4 = –12 c 4 = (4)(–12) 4 c = –48

  15. Check It Out: Example 2B Solve each equation. Check your answer. 6a = –366 6a = –366 366 6a = – 6 6 a = –61

  16. Check It Out: Example 2C Solve each equation. Check your answer. –12d = 144 –12d = 144 –12d = 144 –12–12 d = –12

  17. Check It Out: Example 2D Solve each equation. Check your answer. h 9 = –7 h 9 = –7 h 9 = (9)(–7) 9 h = –63

  18. Additional Example 3: Business Application In 2007, a manufacturer made a profit of $300 million. This amount was $100 million more than the profit in 2006. What was the profit in 2006? Let p represent the profit in 2006 (in millions of dollars). is = More than + 2007 profit 300 100 million 100 2006 profit p 300 = 100 + p –100 –100 200 = p The profit was $200 million in 2006.

  19. Check It Out: Example 3A In July, a department store made a profit of $50 thousand. This amount was $17 thousand less than the profit in June. What was the profit in June? Let p represent the profit in June (in thousands of dollars). Profit in July = p –17 Profit in July = $50 thousand

  20. Check It Out: Example 3A continued p –17= 50 + 17 + 17 p = 67 The profit in June was $67 thousand.

  21. Check It Out: Example 3B In 2008, a manufacturer made a profit of -$450 million. A negative profit is considered a loss. This amount was $125 million more than the profit in 2007. What was the profit in 2007? Let p represent the profit in 2007 (in millions of dollars). Profit in 2008 = p + 125 Profit in 2008 = $–450

  22. Check It Out: Example 3B Continued p + 125= –450 –125 – 125 p = –575 The profit in 2007 was –$575 million.

  23. Lesson Quizzes Standard Lesson Quiz Lesson Quiz for Student Response Systems

  24. Lesson Quiz Solve each equation. Check your answer. 1. –8y = –800 2.x – 22 = –18 3. – = 7 4.w + 72 = –21 5. Last year a phone company had a loss of $25 million. This year the loss is $14 million more last year. What is this years loss? 100 4 y 7 –49 –93 $39 million

  25. Lesson Quiz for Student Response Systems 1. Solve the equation. y + 65= –20 A.y = 45 B.y = 85 C.y = –45 D.y = –85

  26. Lesson Quiz for Student Response Systems 2. Solve the equation. x – 25= –15 A.x = 10 B.x = 20 C.x = 35 D.x = 45

  27. Lesson Quiz for Student Response Systems 3. Solve the equation. –10y = –1000 A.y = –200 B.y = –100 C.y = 100 D.y = 200

  28. Lesson Quiz for Student Response Systems 4. Solve the equation. – — = 6 A.a = 54 B.a = 15 C.a = –15 D.a = –54 a 9

  29. Lesson Quiz for Student Response Systems 5. In an online test, Rick scored –34 points. This was 20 points less than his previous score. What was his previous score? A. 54 points B. 14 points C. –14 points D. –54 points

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