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Substitution Method. Integration. When one function is not the derivative of the other e.g. x is not the derivative of (4 x -1) and x is a variable. Substitute. Example 2. x - 1 is not the derivative of x +4 and it contains a variable. Substitute.
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Substitution Method Integration
When one function is not the derivative of the other e.g. x is not the derivative of (4x -1) and x is a variable Substitute
Example 2 x - 1 is not the derivative of x +4 and it contains a variable Substitute
Example 1 As 2x is the derivative, use inverse chain rule to integrate Substitute x = 4 Substitute x = 2
Example 2 4x divided by 2x = 2 Solving x = 1/2 Substitute x = 1/2 into 4x + 3 to get 5 Divide the top by the bottom
Example 3 Use substitution Substituting
…we could break the area up into rectangular sections. This would overestimate the area.
…or we could break the area up like this which would underestimate the area.
The more sections we divide the area up into, the more accurate our answer would be.
If each of our sections was infinitely narrow, we would have the area of each section as y The total area would be the sum of all these areas between a and b.
is the sum all the areas of infinitely narrow width, dx and height, y.
As the value of dx decreases, the area of the rectangle approaches y x dx y 0 dx
The area of this triangle is 3 units squared The equation of the line is 2 If we sum all rectangles y 0 dx 3
The area of this triangle is 3 units squared The equation of the line is dx 3 0 If we sum all rectangles y The area is 3 but the integral is -3 2
2010 Level 2 • Area cannot be negative • Area = 6.67 units2
-1 -6 8 Combination Integral is positive Integral is negative To find the area under the curve, we must integrate between -6 and -1 and between 8 and -1 separately and add the positive values together.
-1 8 -6
2012 • First find the x-value of the intersection point
2010 Question 1e • Find intersection points
As the value of dy decreases, the area of the rectangle approaches x x dy The equation of the line is 3 Rearrange dy x 0 4 Definite Integral is
A typical rectangle in the upper section Solving these Equations gives y = 1 1 x = y x - x dy Area =(x - x )dy Area for this section is
A typical rectangle in the lower section x = y x - x dy Area =(x - x )dy Area for this section is Total area is equal to 1
Example 2 A typical rectangle dx y - y Area = (y - y)dx 0.707 Area