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GUSS Solves Problems

GUSS Solves Problems. Featuring Significant Digits Big Sig Fig Gig. 1. How many sig digs are in each of the following: a) 4.56 m b) 0.056 cm c) 12.100 g d) 1501 L e) 14 0 0 cm 3 f) 0.01200300 A. 1. How many sig digs are in each of the following: a) 4.56 m 3 sig digs

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GUSS Solves Problems

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  1. GUSS Solves Problems Featuring Significant Digits Big Sig Fig Gig

  2. 1. How many sig digs are in each of the following: a) 4.56 m b) 0.056 cm c) 12.100 g d) 1501 L e) 1400 cm3 f) 0.01200300 A

  3. 1. How many sig digs are in each of the following: a) 4.56 m 3 sig digs b) 0.056 cm c) 12.100 g d) 1501 L e) 1400 cm3 f) 0.01200300 A

  4. 1. How many sig digs are in each of the following: a) 4.56 m 3 sig digs b) 0.056 cm 2 sig digs c) 12.100 g d) 1501 L e) 1400 cm3 f) 0.01200300 A

  5. 1. How many sig digs are in each of the following: a) 4.56 m 3 sig digs b) 0.056 cm 2 sig digs c) 12.100 g 5 sig digs d) 1501 L e) 1400 cm3 f) 0.01200300 A

  6. 1. How many sig digs are in each of the following: a) 4.56 m 3 sig digs b) 0.056 cm 2 sig digs c) 12.100 g 5 sig digs d) 1501 L 4 sig digs e) 1400 cm3 f) 0.01200300 A

  7. 1. How many sig digs are in each of the following: a) 4.56 m 3 sig digs b) 0.056 cm 2 sig digs c) 12.100 g 5 sig digs d) 1501 L 4 sig digs e) 1400 cm3 3 sig digs f) 0.01200300 A

  8. 1. How many sig digs are in each of the following: a) 4.56 m 3 sig digs b) 0.056 cm 2 sig digs c) 12.100 g 5 sig digs d) 1501 L 4 sig digs e) 1400 cm3 3 sig digs f) 0.01200300 A 7 sig digs

  9. 2. Round each measurement to 4 sig digs: a) 15.6732 L = b) 0.0469232 cm = c) 4.5555 g = d) 4.55555 kg =

  10. 2. Round each measurement to 4 sig digs: a) 15.6732 L = 15.67 L b) 0.0469232 cm = c) 4.5555 g = d) 4.55555 kg =

  11. 2. Round each measurement to 4 sig digs: a) 15.6732 L = 15.67 L b) 0.0469232 cm = 0.04692 cm c) 4.5555 g = d) 4.55555 kg =

  12. 2. Round each measurement to 4 sig digs: a) 15.6732 L = 15.67 L b) 0.0469232 cm = 0.04692 cm c) 4.5555 g = 4.556 g d) 4.55555 kg =

  13. 2. Round each measurement to 4 sig digs: a) 15.6732 L = 15.67 L b) 0.0469232 cm = 0.04692 cm c) 4.5555 g = 4.556 g d) 4.55555 kg = 4.556 kg

  14. Dealing with Calculations When a measurement is used in a calculation, the final answer must take into consideration the sig digs in the original measurements. Where The Heck To Round

  15. Dealing with Calculations When a measurement is used in a calculation, the final answer must take into consideration the uncertainty in the original measurements. Why? You don’t want to suggest that you know something to a greater precision than you actually measured. For example, 4 m/3 s = 1.3333333333333333333333 m/s???

  16. Dealing with Calculations When a measurement is used in a calculation, the final answer must take into consideration the uncertainty in the original measurements. Why? You don’t want to suggest that you know something to a greater precision than you actually measured. For example, 4 m/3 s = 1 m/s.

  17. Dealing with Calculations When a measurement is used in a calculation, the final answer must take into consideration the uncertainty in the original measurements. Note: Exact numbers used in calculations (e.g. a factor such as ½ in the equation K=½mv2) are not measurements.

  18. Addition and Subtraction When adding or subtracting measurements, the final answer should be rounded off to the least number of decimals in the original measurements. e.g. 5.124 cm (3 decimal places) + 0.01 cm(2 decimal places) 5.13 cm (2 decimal places)

  19. Practice • 7 m + 7 m = • 7 m + 7.0 m = • 7.0 m + 7.0 m =

  20. Practice • 7 m + 7 m = 14 m • 7 m + 7.0 m = • 7.0 m + 7.0 m =

  21. Practice • 7 m + 7 m = 14 m • 7 m + 7.0 m = 14 m • 7.0 m + 7.0 m =

  22. Practice • 7 m + 7 m = 14 m • 7 m + 7.0 m = 14 m • 7.0 m + 7.0 m = 14.0 m

  23. Multiplication and Division When multiplying or dividing measurements, the final answer should be rounded off to the same number of sig digs as are in the measurement with the least number of sig digs. e.g. 5.124 cm (4 sig digs) x 0.01 cm(1 sig dig) 0.05 cm2(1 sig dig)

  24. Practice • 7 m x 7 m = • 7 m x 7.0 m = • 7.0 m x 7.0 m =

  25. Practice • 7 m x 7 m = 50 m2 (Yes, your math teacher would not approve.) • 7 m x 7.0 m = • 7.0 m x 7.0 m =

  26. Practice • 7 m x 7 m = 50 m2 • 7 m x 7.0 m = 50 m2 • 7.0 m x 7.0 m =

  27. Practice • 7 m x 7 m = 50 m2 • 7 m x 7.0 m = 50 m2 • 7.0 m x 7.0 m = 49 m2

  28. This is GUSS

  29. This is GUSS GUSS has a procedure for solving problems.

  30. This is GUSS GUSS has a procedure for solving problems. First, he identifies his Givens.

  31. This is GUSS GUSS has a procedure for solving problems. First, he identifies his Givens. Then he identifies his Unknown.

  32. This is GUSS GUSS has a procedure for solving problems. First, he identifies his Givens. Then he identifies his Unknown. Next, he Selects an equation that relates his Givens and his Unknown, rearranging it for the Unknown if necessary.

  33. This is GUSS GUSS has a procedure for solving problems. First, he identifies his Givens. Then he identifies his Unknown. Next, he Selects an equation that relates his Givens and his Unknown, rearranging it for the Unknown if necessary. Finally, he substitutes his Givens into the equation and Solves for his Unknown.

  34. An Example: How long does it take an object travelling at a speed of 3.0 m/s to travel a distance of 1.5 km?

  35. An Example: How long does it take an object travelling at a speed of 3.0 m/s to travel a distance of 1.5 km? Givens: speed (v) = 3.0 m/s

  36. An Example: How long does it take an object travelling at a speed of 3.0 m/s to travel a distance of 1.5 km? Givens: speed (v) = 3.0 m/s distance (d) = 1.5 km

  37. An Example: How long does it take an object travelling at a speed of 3.0 m/s to travel a distance of 1.5 km? Givens: speed (v) = 3.0 m/s distance (d) = 1.5 km x 1000 m 1 km

  38. An Example: How long does it take an object travelling at a speed of 3.0 m/s to travel a distance of 1.5 km? Givens: speed (v) = 3.0 m/s distance (d) = 1.5 km x 1000 m 1 km = 1500 m

  39. An Example: How long does it take an object travelling at a speed of 3.0 m/s to travel a distance of 1.5 km? Givens: speed (v) = 3.0 m/s distance (d) = 1.5 km x 1000 m 1 km = 1500 m Unknown: time (t)

  40. An Example: Select an Equation: v = d t

  41. An Example: Select an Equation: v = d t v x t = d x t t

  42. An Example: Select an Equation: v = d t v x t = d x t t vt = d

  43. An Example: Select an Equation: v = d t v x t = d x t t vt = d vt = d v v

  44. An Example: Select an Equation: v = d t v x t = d x t t vt = d vt = d v v t = d v

  45. An Example: Select an Equation: t = d v

  46. An Example: Select an Equation: t = d v Substitute and Solve: t = 1500 m 3.0 m/s

  47. An Example: Select an Equation: t = d v Substitute and Solve: t = 1500 m 3.0 m/s = 500 s

  48. An Example: Select an Equation: t = d v Substitute and Solve: t = 1500 m (2 sig digs) 3.0 m/s (2 sig digs) = 500 s = 500 s (2 sig digs)

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