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Introduction to Mixture Applications. Example 1:. A jar contains 20 ounces of a solution that is part water and part acid. If the amount of acid is 10% of the total solution, how much acid is in the solution?.
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Introduction to Mixture Applications Example 1: A jar contains 20 ounces of a solution that is part water and part acid. If the amount of acid is 10% of the total solution, how much acid is in the solution? First, determine what 10% is as a fraction. Recall than percent means per hundred:
20 ounces total water & acid
The acid is 10% of the total: of the total 20 10%
Review the expression that gave us the amount of acid: of the total 20 20 In decimal form … 10% 10% = (percent acid) × (total amount)
Introduction to Mixture Applications Example 2: A jar contains x ounces of a solution that is part water and part acid. If the amount of acid is 10% of the total solution, how much acid is in the solution?
x ounces total water & acid
The acid is 10% of the total: of the total x 10% = (percent acid) × (total amount)
There are 0.10x ounces of acid in the solution. 0.10x oz. = (percent acid) × (total amount)
Introduction to Mixture Applications Example 3: A jar contains x ounces of a solution that is part water and part acid. If the amount of acid is 65% of the total solution, how much acid is in the solution? Amount acid = (percent acid) × (total amount)