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Entry Task: Feb 11 th Monday. Write the question down: Find the empirical formula of a compound containing: 37.5 % C, 12.6 % H, and 49.9% oxygen. You have ~10 minutes!. Agenda: Go over Empirical Formula ws #2 HW: Empirical Formula pre-lab questions. Empirical Formula.
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Entry Task: Feb 11thMonday Write the question down: Find the empirical formula of a compound containing: 37.5 % C, 12.6 % H, and 49.9% oxygen. You have ~10 minutes!
Agenda:Go over Empirical Formula ws #2HW: Empirical Formula pre-lab questions
Empirical Formula Find the empirical formula of a compound containing: 3.06 % Hydrogen, 31.63 % Phosphorus, and 65.30 % Oxygen. 1 mole of H ------------- 3.06 g of Hydrogen = 3.04 Moles of Hydrogen --------- 1.0079 g of H 1 mole of P ------------- 31.63 g of Phosphorus = 1.02 Moles ofPhosphorus --------- 30.974 g of P 1 mole of O ------------- 65.30 g of Phosphorus = 4.08 Moles ofOxygen --------- 15.999 g of O
Empirical Formula Second: Take the smallest mole amount and divided it into all others. 3.04 Moles of Hydrogen = 2.98 Moles of Hydrogen 1.02 Moles of Phosphorus 4.08 Moles of Oxygen = 4 Moles of Oxygen 1.02 Moles of Phosphorus 1.02 Moles of Phosphorus = 1 Moles of Phosphorus 1.02 Moles of Phosphorus H3PO4
Empirical Formula Find the empirical formula of a compound containing: 28.05 % Sodium, 29.26 % Carbon, 3.66 % Hydrogen, and 39.02 % Oxygen. 1 mole of Na ------------- 28.05 g of Sodium = 1.22 Moles of Sodium --------- 22.9 g of Na 1 mole of C ------------- 29.26 g of Carbon = 2.44 Moles of Carbon --------- 12.011 g of C
Empirical Formula Find the empirical formula of a compound containing: 28.05 % Sodium, 29.26 % Carbon, 3.66 % Hydrogen, and 39.02 % Oxygen. 1 mole of H ------------- 3.66 g of Hydrogen = 3.63 Moles of Hydrogen --------- 1.0079 g of H 1 mole of O ------------- 39.02 g of Oxygen = 2.44 Moles of Oxygen --------- 15.999 g of O
Empirical Formula Take the smallest mole amount and divided it into all others. 2.44 Moles of Carbon = 2.0 Moles of Carbon 1.22 Moles of Sodium 3.63 Moles of Hydrogen = 2.97 Moles of Hydrogen 1.22 Moles of Sodium 2.45 Moles of Oxygen = 2.00 Moles of Oxygen 1.22 Moles of Sodium 1.22 Moles of Sodium = 1 Moles of Sodium 1.22 Moles of Sodium C2H3O2Na
Empirical Formula Find the empirical formula of a compound containing: 24.56 % Potassium, 34.81 % Manganese, and 40.50 % Oxygen. 1 mole of K ------------- 24.56 g of Potassium = 0.628 Moles of Potassium --------- 39.098 g of K 1 mole of Mn ------------- 34.81 g of Manganese = 0.634 MolesManganese --------- 54.9 g of Mn 1 mole of O ------------- 40.50 g of oxygen = 2.5 Moles of Oxygen --------- 15.999 g of O
Empirical Formula Second: Take the smallest mole amount and divided it into all others. 0.634 Moles of Manganese = 1 Moles of Manganese 0.628 Moles of Potassium 2.5 Moles of Oxygen = 3.98 or 4 Moles of Oxygen 0.628 Moles of Potassium 0.628 Moles of Potassium = 1 Moles of Potassium 0.628 Moles of Potassium KMnO4
Empirical Formula Find the empirical formula of a compound containing: 37.70 % Sodium, 22.95 % Silicon, and 39.34 % Oxygen. 1 mole of Na ------------- 37.70 g of Sodium = 1.64 Moles of Sodium --------- 22.9 g of Na 1 mole of Si ------------- 22.95 g of Silicon = 0.817 Moles of Silicon --------- 28.086 g of Si 1 mole of O ------------- 39.34 g of oxygen = 2.45 Moles of Oxygen --------- 15.999 g of O
Empirical Formula Second: Take the smallest mole amount and divided it into all others. 1.64 Moles of Sodium = 2 Moles of Sodium 0.817 Moles of Silicon 2.45 Moles of Oxygen = 2.99 or 3 Moles of Oxygen 0.817 Moles of Silicon 0.817 Moles of Silicon = 1 Moles of Silicon 0.817 Moles of Silicon Na2SiO3
Empirical Formula Find the empirical formula of a compound containing: 21.21 % Nitrogen, 6.06 % Hydrogen, 24.24% Sulfur, and 48.48 % Oxygen. 1 mole of N ------------- 21.21 g of Nitrogen = 1.51 Moles of Nitrogen --------- 14.007 g of N 1 mole of H ------------- 6.06 g of Hydrogen = 6.01 Moles of Hydrogen --------- 1.0079 g of H
Empirical Formula Find the empirical formula of a compound containing: 21.21 % Nitrogen, 6.06 % Hydrogen, 24.24% Sulfur, and 48.48 % Oxygen. 1 mole of S ------------- 24.24 g of Sulfur = 0.756 Moles of Sulfur --------- 32.065 g of S 1 mole of O ------------- 48.48 g of Oxygen = 3.03 Moles of Oxygen --------- 15.999 g of O
Empirical Formula Take the smallest mole amount and divided it into all others. 1.51 Moles of Nitrogen = 2.0 Moles of Nitrogen 0.756 Moles of Sulfur 6.01 Moles of Hydrogen = 7.95 or 8 Moles of Hydrogen 0.756 Moles of Sulfur 3.03 Moles of Oxygen = 4 Moles of Oxygen 0.756 Moles of Sulfur 0.756 Moles of Sulfur = 1 Moles of Sulfur 0.756 Moles of Sulfur N2H8SO4