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Basic Orbital Mechanics. Dr. Andrew Ketsdever MAE 5595. Conic Sections. Elliptical Orbit Geometry. Conic Sections. Classical Orbital Elements. Semi-Major Axis, a Size Eccentricity, e Shape. Kepler’s 3 rd Law. Classical Orbital Elements. Inclination Tilt. Classical Orbital Elements.
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Basic Orbital Mechanics Dr. Andrew Ketsdever MAE 5595
Classical Orbital Elements • Semi-Major Axis, a • Size • Eccentricity, e • Shape Kepler’s 3rd Law
Classical Orbital Elements • Inclination • Tilt
Classical Orbital Elements • Right Ascension of the Ascending Node (RAAN)
Classical Orbital Elements • Argument of Perigee
Classical Orbital Elements • True Anomaly
Computing COEs • From a R and V vector • Can compute the 6 COEs • Also works in reverse (given COEs compute R and V) • Example:
COEs • a = 7965.1 km • e = 0.0584 • i = 90º • = 270º • = 90º • = 0º • Mission: Probably remote sensing or a spy satellite because it’s in a low, polar orbit.
Ground Tracks Ground Track Slides Courtesy of Major David French
ΔN 15º / hr P = COE Determination ΔN Δ longitude Semimajor axis
COE Determination Eccentricity
i = highest latitude COE Determination Inclination
ω = 90º COE Determination Argument of Perigee
COE Determination True Anomaly
Geosynchronous e = 0 e = 0.4 w = 180° e = 0 i = 0° e = 0.6 w = 90°
Orbit Prediction • Kepler’s Problem • If we know where a satellite (or planet) is today, where in its orbit will it be tomorrow? • Kepler devised a series of mathematical expressions to solve this particular problem • Eccentric Anomaly • Mean Anomaly • True Anomaly
Orbit Prediction • Kepler defined the Eccentric Anomaly to relate elliptical motion to circular motion • He also defined Mean Anomaly to make the circular motion constant • Convert unsteady elliptical motion into unsteady circular motion into steady circular motion…
Orbital Prediction • Given a = 7000 km e = 0.05 • = 270º Find the time of flight to final = 50º
Orbital Prediction • n = 0.001078 rad/sec • Einitial = 272.87º • Efuture = 47.84º • Minitial = 275.73º • Mfuture = 45.72º • TOF = 2104.58 sec or 35.08 min