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Warm up

Preliminary Activity. Notes. For Fun. Warm up. Activity. Area of a Triangle. Back. Back. 1. The compass bearing for this diagram is A WS B EN C SW D NE 2. The true bearing of A from O in the diagram is A 053 o T B 127 o T C 307 o T D 53 o T

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Warm up

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  1. Preliminary Activity Notes For Fun Warm up Activity Area of a Triangle

  2. Back Back 1. The compass bearing for this diagram is A WS B EN C SW D NE 2. The true bearing of A from O in the diagram is A 053oT B 127oT C 307oT D 53oT 3. A ship sails 57 km from a port A on a bearing of 298oT. The distance the ship is North of its starting point is A 26.8 km B 64.6 km C 107.2 km D 121.4 km 4. A town X is 58 km East and 113 km South of town Y. The bearing of X from Y is closest to A SE B NE C 063oT D 153oT 5. The value of θ is closest to A 36o51' B 43o16' C 81o6' D 99o54' 6. The value of θ in this triangle is closest to A 40o19' B 18o39' C 18o40' D 28o

  3. Back Back The formula for the area of a triangle base b, perpendicular height h, is Area = ½bh. Examine the area of a triangle ABC with base AC and perpendicular height h. Area of ΔABC = ½ x base x height = ½ x CA x BX = ½bh...... (1) In ΔBXC, sin C = opp hyp ∴ sin C = h a ∴h = a sin C ......(2) Combining (1) and (2) gives Area = ½b(a sinC) i.e., Area = ½ab sinC i.e., given two sides and the included angle of a triangle, the area is given by Area = ½ab sinC Similarly, the area is given by Area = ½ac sinB and Area = ½bc sinA

  4. Back Back Find the area of the following triangle: a) b) Area = ½pr sinQ Area = ½absinC = ½ x 11 x 8 x sin130o = ½ x 14 x 12 x sin57o = 33.7cm2 (1 decimal place) = 70.4cm2 (1 decimal place)

  5. Back Back Complete exercise 5-08 Questions 1, 2, 4, 6, 8, 10, 11 41.7% 56.3% 75.7%

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