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Learn to formulate and solve absolute value linear equations, understand constraints, and identify extraneous solutions. Practice various cases and examples to develop a solid foundation in solving absolute value equations.
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LESSON 1–4 Solving Absolute Value Equations
Targeted TEKS A2.6(D) Formulate absolute value linear equations. A2.6(E) Solve absolute value linear equations. Mathematical Processes A2.1(B), A2.1(D) TEKS
absolute value • empty set • constraint • extraneous solution Vocabulary
? ? |5 + 3| = 8 |–11 + 3| = 8 ? ? |8| = 8 |–8| = 8 8 = 8 8 = 8 Solve an Absolute Value Equation Case 1 a = b y + 3 = 8 y + 3 – 3 = 8 – 3 y = 5 Case 2 a = –b y + 3 = –8 y + 3 – 3 = –8 – 3 y = –11 Check |y + 3| = 8 |y + 3| = 8 Answer: The solutions are 5 and –11.Thus, the solution set is –11, 5. Example 2
What is the solution to |2x + 5| = 15? A. {5} B. {–10, 5} C. {–5, 10} D. {–5} Example 2
No Solution Solve |6 – 4t| + 5 = 0. |6 – 4t| + 5 = 0 Original equation |6 – 4t| = –5 Subtract 5 from each side. This sentence is never true. Answer: The solution set is . Example 3
A. B. C. D. Example 3
One Solution Case 1 a = b 8+ y = 2y – 3 8 = y – 3 11 = y Example 4
One Solution Check: Answer: Example 4
A. B. C. D. Example 4
LESSON 1–4 Solving Absolute Value Equations