1 / 41

Navigation Computer

Navigation Computer. Terminal Learning Objective: Compute pertinent information essential to flight planning and actual flight In Accordance With FM 3-04.240. 1. 5. 9. 13. 6. 2. 10. 14. 3. 7. 11. 15. 4. 8. 12. 16. 1. Convert 74 NM to statute miles.

colette-collins
Download Presentation

Navigation Computer

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Navigation Computer

  2. Terminal Learning Objective: Compute pertinent information essential to flight planning and actual flight In Accordance With FM 3-04.240.

  3. 1 5 9 13 6 2 10 14 3 7 11 15 4 8 12 16

  4. 1. Convert 74 NM to statute miles.

  5. 1. Convert 74 NM to statute miles. 85 SM BACK

  6. 2. What is the ground speed if a distance of 35 NM is flown in 19 minutes?

  7. 2. What is the ground speed if a distance of 35 NM is flown in 19 minutes? 111 Kts BACK

  8. 3. Find the time required to fly 5.5 NM at a ground speed of 110 knots.

  9. 3. Find the time required to fly 5.5 NM at a ground speed of 110 knots. 3 min BACK

  10. 4. Find the fuel needed to fly 03+10 at a consumption rate of 24 GPH.

  11. 4. Find the fuel needed to fly 03+10 at a consumption rate of 24 GPH. 76 Gal BACK

  12. Find TRUE airspeed: • CAS = 110 knots • PA = 6500 feet • FAT = +10° C Patience – next slide loads slowly.

  13. Find TRUE airspeed: • CAS = 110 knots • PA = 6500 feet • FAT = +10° C TAS=123 Kts BACK

  14. Given: • True Course = 330° • Wind = 270/20 • TAS = 90 knots • Find : True heading • Find : Ground speed

  15. Given: • True Course = 330° • Wind = 270/20 • TAS = 90 knots • Find : True heading • Find : Ground speed 319˚ 79 Kts BACK

  16. 7. Given: • True Course = 183° • Wind = 150/25 • Ground Speed = 135 knots • Find : True heading • Find : True airspeed

  17. 7. Given: • True Course = 183° • Wind = 150/25 • Ground Speed =135 knots • Find : True heading • Find : True airspeed 178˚ 156 Kts BACK

  18. 8. Given: • Track = 025° • Ground speed = 87 knots • True Heading = 033° • True airspeed = 95 knots • Find : Wind speed • Find : Direction

  19. 8. Given: • Track = 025° • Ground speed = 87 knots • True Heading = 033° • True airspeed = 95 knots • Find : Wind speed • Find : Direction 15 Kts 087˚ BACK

  20. Find ETE. Given: • True Course = 290° • Wind = 270/20 • Distance = 180 nm • Altitude = 8000 msl • Temp = +10° C • CAS = 90 knots • Find : True heading • Find : True airspeed

  21. Find ETE. Given: • True Course = 290° • Wind = 270/20 • Distance = 180 nm • Altitude = 8000 msl • Temp = +10° C • CAS = 90 knots • Find : True heading • Find : True airspeed TAS=104 Kts

  22. Find ETE. Given: • True Course = 290° • Wind = 270/20 • Distance = 180 nm • Altitude = 8000 PA • Temp = +10° C • CAS = 90 knots • Find : True heading • Find : True airspeed True Hdg = 285˚ GS = 84 Kts TAS = 104 Kts

  23. Find ETE. Given: • True Course = 290° • Wind = 270/20 • Distance = 180 nm • Altitude = 8000 msl • Temp = +10° C • CAS = 90 knots • Find : True heading • Find : True airspeed ETE 2 Hrs 9 min GS = 84 Kts BACK

  24. 10. Given: 82.6 gal JP8 • Find : Fuel in pounds

  25. 10. Given: 82.6 gal JP8 • Find : Fuel in pounds 553 Lbs 82.6 Gal BACK

  26. 11. Given (holding situation): • Outbound time = 60 sec • Inbound time = 26 sec • Find : Next outbound time

  27. Given (holding situation): • Outbound time = 60 sec • Inbound time = 26 sec • Find : Next outbound time 139 sec or2 min 19 sec BACK

  28. 12. Given: • Wind = 240/12 • Temp = +15° C • Approach course = 051° • CAS = 90 knots • FAF to MAP = 4.6 nm • PA = 1,000 feet • Find : Time required to fly from FAF to MAP

  29. 12. Given: • Wind = 240/12 • Temp = +15° C • Approach course = 051° • CAS = 90 knots • FAF to MAP = 4.6 nm • PA = 1,000 feet • Find : Time required to fly from FAF to MAP TAS = 91 Kts

  30. 12. Given: • Wind = 240/12 • Temp = +15° C • Approach course = 051° • CAS = 90 knots • FAF to MAP = 4.6 nm • PA = 1,000 feet • Find : Time required to fly from FAF to MAP TAS = 91 Kts GS = 103 Kts

  31. 12. Given: • Wind = 240/12 • Temp = +15° C • Approach course = 051° • CAS = 90 knots • FAF to MAP = 4.6 nm • PA = 1,000 feet • Find : Time required to fly from FAF to MAP GS = 103 FAF to MAP 2 min 42 sec BACK

  32. 13. Given: • Surface wind = 270/15 • TAS = 96 knots • Final approach Course = 260° • Glideslope = 2.7° • Find : Rate of descent (FPM) required to stay on glideslope

  33. 13. Given: • Surface wind = 270/15 • TAS = 96 knots • Final approach Course = 260° • Glideslope = 2.7° • Find : Rate of descent (FPM) required to stay on glideslope GS = 81 Kts

  34. Given • Surface wind = 270/15 • TAS = 96 knots • Final approach Course = 260° • Glideslope = 2.7° Find : Rate of descent (FPM) required to stay on glideslope GS = 81Kts 364 fpm BACK

  35. 14. Given: • Useable fuel = 73 gal • Consumption rate = 26 gph • Find : Hours and minutes of flight time available

  36. 14. Find: Hours and minutes of total flight time available at a consumption rate of 26 GPH with 73 gal available fuel. 2 Hrs 47 min BACK

  37. 15. Given: • Wind 080/15 • TAS 93 knots • Final course = 061° • FAF to MAP = 5.4 nm • Find : Time from FAF to MAP

  38. 15. Given: • Wind 080/15 • TAS 93 knots • Final course = 061° • FAF to MAP = 5.4 nm • Find : Time from FAF to MAP GS = 78 Kts

  39. 15. Given: • Wind 080/15 • TAS = 93 knots • Final course = 061° • FAF to MAP = 5.4 nm • Find : Time from FAF to MAP GS = 78 Kts 4 min 10 sec BACK

  40. 16. Given: • Takeoff minimums requiring a climb rate of 400 feet per NM • GS = 70 knots • Find : Rate of climb required

  41. 16. Given: • Takeoff minimums requiring a climb rate of 400 feet per NM • GS = 70 knots • Find : Rate of climb required 465 fpm BACK

More Related