1 / 20

Ordered Pairs

Ordered Pairs. 1-7. Pre-Algebra. Warm Up. Solve. 1. x  8 = 19. x = 27. a = 7. 2. 5 = a  2. n = 17. 3. 7 + n = 24. c = 13. 4. 3 c  7 = 32. y = 3. 5. 17 y + 7 = 58. Learn to write solutions of equations in two variables as ordered pairs . Vocabulary. ordered pair.

collier
Download Presentation

Ordered Pairs

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Ordered Pairs 1-7 Pre-Algebra

  2. Warm Up Solve. 1.x  8 = 19 x = 27 a = 7 2. 5 = a  2 n = 17 3. 7 + n = 24 c = 13 4. 3c  7 = 32 y = 3 5. 17y + 7 = 58

  3. Learn to write solutions of equations in two variables as ordered pairs.

  4. Vocabulary ordered pair

  5. A sign at the store reads “Birthday Banners $8. Personalize for $1 per letter.” Cecilia has 7 letters in her name, and Dowen has 5 letters in his. Figure out how much it will cost to get a personalized birthday banner for each of them.

  6. Number of letters in name $8 $1 Price of banner = + • Let y be the price of the banner and x be the number of letters in the name; the equation for the price of a banner is y = 8 + x. For Cecelia’s banner: x = 7, y = 8 + 7 or y = 15 For Dowen’s banner: x = 5, y = 8 + 5 or y = 13

  7. A solution of a two-variable equation is written as an ordered pair. When the numbers in the ordered pair are substituted in the equation, the equation is true. (7, 15) is a solution  15 = 7 + 8 (5, 13) is a solution  13 = 5 + 8  (x, y) Ordered pair

  8. ? 11= 11 ? 11 = 4(3) – 1 Determining If an Ordered Pair Is a Solution of an Equation Determine whether the ordered pair is a solution of y = 4x – 1. A. (3, 11) y = 4x – 1 Substitute 3 for x and 11 for y. A solution since 11=11.  (3, 11) is a solution.

  9. ? 3 = 4(10) – 1 ? 3 = 39 Determining If an Ordered Pair Is a Solution of an Equation Determine whether the ordered pair is a solution of y = 4x – 1. B. (10, 3) y = 4x – 1 Substitute 10 for x and 3 for y.  (10, 3) is not a solution.

  10. ? 43 = 4(11) – 1 ? 43 = 43 Determining If an Ordered Pair Is a Solution of an Equation Determine whether the ordered pair is a solution of y = 4x – 1. C. (11, 43) y = 4x – 1 Substitute 11 for x and 43 for y. A solution since 43 = 43.  (11, 43) is a solution.

  11. ? 38 = 5(7) + 3 ? 38 = 38 Example 1 Determine whether the ordered pair is a solution of y = 5x + 3. A. (7, 38) y = 5x + 3 Substitute 7 for x and 38 for y.  (7, 38) is a solution.

  12. ? 17 = 5(9) + 3 ? 17 = 48 Example 2 Determine whether the ordered pair is a solution of y = 5x + 3. B. (9, 17) y = 5x + 3 Substitute 9 for x and 17 for y.  (9, 17) is not a solution.

  13. ? 53 = 5(10) + 3 ? 53 = 53 Example 3 Determine whether the ordered pair is a solution of y = 5x + 3. C. (10, 53) y = 5x + 3 Substitute 10 for x and 53 for y.  (10, 53) is a solution.

  14. x 7x y (x, y) 1 2 3 4 Creating a Table of Ordered Pair Solutions Use the given values to make a table of solutions. A.y = 7x for x = 1, 2, 3, 4 7(1) 7 (1, 7) 7(2) 14 (2, 14) 7(3) 21 (3, 21) 7(4) 28 (4, 28)

  15. m 1 2 3 4 6m – 5 n (m, n) Creating a Table of Ordered Pair Solutions Use the given values to make a table of solutions. B.n = 6m –5for m = 1, 2, 3, 4 6(4) – 5 6(1) – 5 6(2) – 5 6(3) – 5 1 7 13 19 (2, 7) (4, 19) (1, 1) (3, 13)

  16. m 1 2 3 4 8m – 2 n (m, n) Example 5 Use the given values to make a table of solutions. B.n = 8m –2for m = 1, 2, 3, 4 8(4) – 2 8(1) – 2 8(2) – 2 8(3) – 2 6 14 22 30 (2, 14) (4, 30) (1, 6) (3, 22)

  17. Retail Application A salesman wants to make a 20% profit on everything he sells. The equation for the sales price p is p = 1.2w, where wis wholesale cost. A. What will be the sales price of a sweater with a wholesale cost of $48? p = 1.2(48) The price of the sweater before tax is $48. p = 57.6 The sweater is $48, and after tax it will cost $57.60, so (48, 57.60) is a solution of the equation.

  18. Continued A salesman wants to make a 20% profit on everything he sells. The equation for the sales price p is p = 1.2w, where wis wholesale cost. B. What will be the sales price of a jacket with a wholesale cost of $85? p = 1.2(85) The price of the jacket before tax is $85. p = 102 The jacket is $85.00, and after tax it will cost $102, so (85, 102) is a solution of the equation.

  19. Example 6 In most states, the price of each item is not the total cost. Sales tax must be added. If sales tax is 7.5 percent, the equation for total cost is c = 1.075p, where p is the price before tax. A. How much will a $22 item cost after sales tax? c = 1.075(22) The price of the item before tax is $22. c = 23.65 After sales tax, the $22 item will cost $23.65, so (22, 23.65) is a solution to the equation.

  20. Lesson Quiz Determine whether each ordered pair is a solution for y = 4x  7 . 1.(2, 15) 2. (4, 9) 3. Use the given values to make a table of solutions. y = 4x 6 for x = 2, 4, 6, 8, and 10 no yes

More Related