1 / 20

Thermal Aspects of Cadmium Zinc Telluride (CZT) Imager Presented By M.K. Hingar

Thermal Aspects of Cadmium Zinc Telluride (CZT) Imager Presented By M.K. Hingar. Plan. Configuration Design Inputs Design of the Detector Board Analysis Results Radiator & Heat Pipe Design Critical Elements Conclusions. CONFIGURATION. Thermal design Inputs for CZT-Imager.

corbin
Download Presentation

Thermal Aspects of Cadmium Zinc Telluride (CZT) Imager Presented By M.K. Hingar

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Thermal Aspects of Cadmium Zinc Telluride (CZT) Imager Presented By M.K. Hingar

  2. Plan • Configuration • Design Inputs • Design of the Detector Board • Analysis Results • Radiator & Heat Pipe Design • Critical Elements • Conclusions

  3. CONFIGURATION

  4. Thermal design Inputs for CZT-Imager

  5. CZT DETECTOR CZT DETECTOR BOARD WITHIN CZT DETECTOR BOARD 5 o 4 o 5o RADIATOR HEAT PIPE 5 o • Thermal Analysis has five Steps: • Transfer of heat from CZT Detector to the CZT Detector Board. • Transfer of heat within the CZT Detector Board. • Transfer of heat from CZT Detector Boardto the Heat pipes. • Transfer of heat from Heat pipes to Radiator. • Radiator design. TEMPERATURE DIFFERENCE BETWEEN DIFFERENT STAGES IN ONE QUADRANT

  6. Transfer of heat from CZT Detector to the CZT Detector Board q = k A ΔT Where q = Power = 0.780 W, k = Thermal Conductivity of thermal epoxy = 0.08 W / cm2 oK A = Area = 4 cm2 ΔT = 0.78 / (0.08 * 4) = 2.42 o K If we consider factor of safety 2, it may be about 5 o K.

  7. Design of Detector Board • Cu-In-Cu • Copper Coating

  8. PROPERTIES OF CIC LAMINATE

  9. Transfer of heat within the CZT Detector Board • The Detector Board of 20Cu/60In/20Cu. • The thickness of Detector Board is 3mm. • The preliminary analysis give the maximum temperature on the Detector Board of the quadrant is about 4o.

  10. Boundary Conditions • Temperature at the edges of Detector Board is 0o • CZT Power (780 mW) distributed equally in 20mm X 20mm area

  11. Analysis shows • Heat Drain from two opposite sides of the Detector Board is necessary. • Radiation losses not considered.

  12. Implications of quadrants failures for thermal design • Suppose one of the quadrants fails then radiator will dissipate about 37 W (50 W ), the Radiator will have temperature of - 27o ( - 20o ). • Suppose two of the quadrants fail then radiator will dissipate about 25 W (50 W), the Radiator will have temperature of - 40o ( - 20o ). • Possible use of heaters to be considered after final simulation.

  13. CONCLUSIONS • Total temperature difference is within 15 o to 20 o . • Procuring one Detector Board and measure temperature difference.

  14. !!!!! THANKS !!!!!

More Related