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Solving Inequalities by Adding or Subtracting. COURSE 2 LESSON 2-9. (For help, go to Lesson 2-3.). Solve each equation. 1. c + 4 = –2 2. x + 9 = 10 3. b + (–2) = 7 4. g – 5 = 10 5. w – 4 = 12 6. m – (–3) = 10. 2-9. Solving Inequalities by Adding or Subtracting.
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Solving Inequalities by Adding or Subtracting COURSE 2 LESSON 2-9 (For help, go to Lesson 2-3.) Solve each equation. 1.c + 4 = –2 2.x + 9 = 10 3.b + (–2) = 7 4.g – 5 = 10 5.w – 4 = 12 6.m – (–3) = 10 2-9
Solving Inequalities by Adding or Subtracting COURSE 2 LESSON 2-9 Solutions 1.c + 4 = –2 2.x + 9 = 10 c + 4 – 4 = –2 – 4 x + 9 – 9 = 10 – 9 c = –6 x = 1 3. b + (–2) = 7 4.g – 5 = 10 b + (–2) – (–2) = 7 – (–2) g – 5 + 5 = 10 + 5 b = 9 g = 15 5.w – 4 = 12 6. m – (–3) = 10 w – 4 + 4 = 12 + 4 m – (–3) + (–3) = 10 + (–3) w = 16 m = 7 2-9
> > > > – – – – q – 2 –6 q – 2 + 2 –6 + 2 Add 2 to each side. q –4Simplify. Solving Inequalities by Adding or Subtracting COURSE 2 LESSON 2-9 Solve q – 2 –6. Graph the solution. 2-9
d + 9 – 9 < 8 – 9 Subtract 9 from each side. d < –1 Simplify. Solving Inequalities by Adding or Subtracting COURSE 2 LESSON 2-9 Solve d + 9 < 8. Graph the solution. d + 9 < 8 2-9
< < < < – – – – 79 – 79 + c 120 – 79 Subtract 79 from each side. • Words amount spent plus amount spent is at most 120 • already on costumes • Let c = amount the Drama Club can spend on costumes. • Inequality 79 + c 120 c 41 Simplify. 79 + c 120 Solving Inequalities by Adding or Subtracting COURSE 2 LESSON 2-9 The Drama Club can spend no more than $120 for costumes. They already spent $79. How much more can they spend for costumes? They can spend at most $41. 2-9
> – < < – – > – a > 23 x < 4 p 9 n 17 Solving Inequalities by Adding or Subtracting COURSE 2 LESSON 2-9 Solve each inequality. Graph the solution. 1.x + 6 < 10 2.a – 9 > 14 3.n + 8 25 4.p – 4 5 2-9