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A reminder of the important laws of refraction

A reminder of the important laws of refraction. Using a vacuum as medium 1 we get the absolute refractive index n of a substance:. If one of the media is air we can just assume its refractive index is 1 and use these equations. refractive index of glass = 1.5.

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A reminder of the important laws of refraction

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  1. A reminder of the important laws of refraction Using a vacuum as medium 1 we get the absolute refractive index n of a substance: If one of the media is air we can just assume its refractive index is 1 and use these equations

  2. refractive index of glass = 1.5 Calculate the speed of light in the glass.

  3. refractive index of glass = 1.5 (b) Determine (i) the angle of incidence, θ, (ii) the refractive index of the liquid. ≈230 =1.3

  4. Same angles as at left hand side into the air. Total internal reflection at the base of the prism

  5. (refractive index of the glass in block 1 = 1.45) (a) Calculate (i) the incident angle θ1, θ1=22.8

  6. (refractive index of the glass in block 1 = 1.45) (ii) the refractive index of the glass in block 2, n1=1.60

  7. (iii) the angle θ3 by considering the refraction at point A. usually we write in this case θ3=59.40

  8. In which of the two blocks of glass will the speed of light be greater? The one which has the lowest refractive index because: implies So where n is smaller c2 will be larger

  9. c) Using a ruler, draw the path of a ray partially reflected at A on Figure 1. Continue the ray to show it emerging into the air. No calculations are expected. (2 marks) reflection at boundary with i = r refraction (at bottom surface) bending away from normal

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