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Balancing Redox rx 8-2

Balancing Redox rx 8-2. Steps to balancing in an acidic solution. Write half-reactions without including electrons. Balance the number of all atoms except oxygen and hydrogen. Balance oxygen atoms by adding water molecules. Balance hydrogen atoms by adding H +.

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Balancing Redox rx 8-2

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  1. Balancing Redox rx8-2

  2. Steps to balancing in an acidic solution. • Write half-reactions without including electrons. • Balance the number of all atoms except oxygen and hydrogen. • Balance oxygen atoms by adding water molecules. • Balance hydrogen atoms by adding H+

  3. Balance charge by adding electrons. • Equalize electrons in the half-reactions by multiplication. • Combine the two half reactions. • Check to see that atoms and charges balance.

  4. Cu + NO3- → Cu2+ + NO • Balance the reaction: • Write the two half reactions • Cu → Cu2+ • NO3- → NO

  5. Cu → Cu2+ There is no oxygen or hydrogen in this reaction, so leave it alone. • Balance oxygen using water • NO3- → NO + 2 H2O Balance hydrogen using H+ • 4 H+ + NO3- → NO + 2 H2O

  6. Balance charge by adding electrons • Cu → Cu2+ + 2e- • 3e- + 4 H+ + NO3- → NO + 2 H2O

  7. Equalize the electrons • Lowest common multiple is 6 3[Cu → Cu2+ + 2e-] 2[3e- + 4 H+ + NO3- → NO + 2 H2O]

  8. Multiple each species by the multiple so that the electrons are equal in both half reactions. 3 Cu → 3 Cu2+ + 6e- 6e- + 8 H+ + 2 NO3- → 2 NO + 4 H2O ____________________________________ 3 Cu+ 8 H+ + 2 NO3- → 3 Cu2+ + 2 NO + 4 H2O Anything that exists as a product and as a reactant can be crossed off

  9. Balance the following: • Cr2O72-(aq) + S2O32-(aq) Cr 3+(aq) + S2O62-(aq) b) Mn3+ (aq) MnO2 (s) + Mn2+ aq) c) C3H8(aq) + O2(aq) CO2(aq) + H2O(l) State what is the reducing agent and the oxidation agent for the above reactions.

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