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Solving Applied problems

Example: Working with Fractions. Solving Applied problems . PROBLEM. Adam wants to fence a triangular shaped yard. He wants to determine how many feet of fencing he will need. The sides of his yard measure as shown in the diagram below. How many feet of fencing should Adam buy? . 7 ½ ft.

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Solving Applied problems

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  1. Example: Working with Fractions Solving Applied problems

  2. PROBLEM Adam wants to fence a triangular shaped yard. He wants to determine how many feet of fencing he will need. The sides of his yard measure as shown in the diagram below. How many feet of fencing should Adam buy? 7 ½ ft 10 3/4 ft 13 1/8 ft

  3. SOLUTION In order to find out how many feet of fencing should be bought, we need to find out the distance around the backyard. This is the same as finding the distance around the triangle, or finding the perimeter of the triangle. 7 ½ ft 10 3/4 ft Note: To find the perimeter of a triangle, we need to add the lengths of all sides of the triangle. 13 1/8 ft

  4. Based on the diagram we have the following: Length of first side = 7 ½ ft Length of second side = 13 1/8 ft Length of third side = 10 ¾ ft. The perimeter of the triangle = sum of all sides of the triangle Notice that we have fractions with different denominators Since the denominators for the fractions are different, we need to first find the LCD. The denominators are 2, 4, and 8. The least common denominator is 8. So we can rewrite the fractions so that they will all have a denominator of 8.

  5. So to find the sum of 7 ½ ft ,13 1/8 ft , and 10 ¾ ft, we add the whole number part and then the fractional part. Therefore, the perimeter of the triangle is 31 5/8 feet. And so Adam will have to purchase 31 5/8 ft of fencing for the yard.

  6. Solving applied problems involving fractionsOpen University Malaysiais licensed under a Creative Commons Attribution-Noncommercial 3.0 Unported License. Based on a work at http://oer.oum.edu.my. Permissions beyond the scope of this license may be available at http://www.oum.edu.my.

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