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CHAPTER 11 NOTES

CHAPTER 11 NOTES. Section 2: Acceleration. Acceleration-The rate at which velocity changes An object accelerates when there is a change in speed, direction, or both!. Calculating acceleration Acceleration= final velocity-initial velocity Time

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CHAPTER 11 NOTES

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  1. CHAPTER 11 NOTES

  2. Section 2: Acceleration • Acceleration-The rate at which velocity changes • An object accelerates when there is a change in speed, direction, or both!

  3. Calculating acceleration • Acceleration=final velocity-initial velocity Time • The slope of a speed time graph would be acceleration • Constant acceleration(steady change in velocity) =straight line

  4. Velocity formula • Velocity=distance/time • V=d/t • Put it in the triangle…. d v t

  5. UNITS OF VELOCITY • d= meters (m) • t= seconds (s) • v=meters/second (m/s • VELOCITY MUST ALWAYS INCLUDE A DIRECTION!!! • Use the same formula to calculate speed just don’t put a direction!!!

  6. Metal stakes are sometimes placed in glaciers to help measure a glacier’s movement. For several days in 1936 Alaska’s Black Rapids glacier surged as swiftly as 89 meters per day. Find the velocity in m/s. • V=d/t • Convert days to seconds! • 1 day=24 hours x 60 min x 60s • 1 hour 1 min • V=d/t=89 m/86400 s • V=.001m/s down the valley

  7. YOU TRY THESE!! • 1.) Find the velocity in m/s of a swimmer who swims 110 m toward the shore in 72 s. • 2.) Find the velocity in m/s of a baseball thrown 38 m from third base to first base in 1.7 s. • 3.) Calculate the distance in meters of a cyclist would travel in 5 h with a velocity of 12 km/h to the southwest.

  8. 1.) Find the velocity in m/s of a swimmer who swims 110 m toward the shore in 72 s. • V=d/t • V=110/72 • V=1.5 m/s toward the shore

  9. 2.)Find the velocity in m/s of a baseball thrown 38 m from third base to first base in 1.7 s. • V=d/t • V=38/1.7 • V=22 m/s toward first base

  10. 3.) Calculate the distance in meters of a cyclist would travel in 5 h with a velocity of 12 km/h to the southwest. • d=vt • d=12(5) • d=60 km • d=60 km (1000 m) • D=60000

  11. ACCELERATION… • a=vf-vi/t • t=vf-vi/a • Vf=vi + at

  12. A flower pot falls off a second story windowsill. The flowerpot starts from rest and hits the sidewalk 1.5 s later with a velocity of 14.7 m/s. Find the acceleration. • a=vf-vi/t • a=(14.7 m/s-0 m/s)÷1.5 s • A=9.8 m/s2 down

  13. Let’s do another one… • Natalie accelerates her skateboard straight along a straight path from 0 m/s to 4 m/s in 2.5 s. Find her acceleration. • a=vf-vi/t • a=(4 m/s-0 m/s) ÷ 2.5 • a=1.6 m/s2 along her path

  14. TRY THESE ON YOUR PAPER! • 1.) A turtle swimming in a straight line toward shore has a speed of .5 m/s. After 4 s it’s speed is .8 m/s, what is the turtle’s acceleration? • 2.) Find the acceleration a northbound train that slows down from 12 m/s to 9.6 m/s in 8 s. • 3.) Marisa’s car accelerates an average rate of 2.6 m/s2. Calculate how long it takes to speed up from 24.6 m/s to 26.8 m/s.

  15. A turtle swimming in a straight line toward shore has a speed of .5 m/s. After 4 s it’s speed is .8 m/s, what is the turtle’s acceleration? • a=vf-vi/t • a=(.8 m/s - .5 m/s)÷4 • a=.075 m/s2 toward the shore

  16. 2.) Find the acceleration a northbound train that slows down from 12 m/s to 9.6 m/s in 8 s. • a=vf-vi/t • a=(9.6-12)÷8 • a=-.3 m/s2 North

  17. 3.) Marisa’s car acclerates an average rate of 2.6 m/s2. Calculate how long it takes to speed up from 24.6 m/s to 26.8 m/s. • t=vf-vi/a • t=(26.8-24.6) ÷2.6 • t=.84 s

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