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Scalar Product. Scalar / Dot Product of Two Vectors. Product of their magnitudes multiplied by the cosine of the angle between the Vectors. Orthogonal Vectors. Angular Dependence. Scalar Product. Scalar Product of a Vector with itself ? A . A = | A || A | cos 0 º = A 2. Scalar Product.
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Scalar Product Scalar / Dot Product of Two Vectors Product of their magnitudes multiplied by the cosine of the angle between the Vectors
Orthogonal Vectors Angular Dependence
Scalar Product Scalar Product of a Vector with itself ? A . A = |A||A| cos 0º = A2
Scalar Product Scalar Product of a Vector and Unit vector ? x . A =|x||A|cosα = Ax Yields the component of a vector in a direction of the unit vector Where alpha is an angle between A and unit vector x ^ ^
Scalar Product Scalar Product of Rectangular Coordinate Unit vectors? x.y = y.z = z.x = ? = 0 x.x = y.y = z.z = ? = 1
Scalar Product Problem 3: A . B = ? ( hint: both vectors have components in three directions of unit vectors)
Scalar Product Problem 4: A = y3 + z2; B= x5 + y8 A . B = ?
Scalar Product Problem 5: A = -x7 + y12 +z3; B = x4 + y2 + z16 A.B = ?
Spherical Coordinates For many mathematical problems, it is far easier to use spherical coordinates instead of Cartesian ones. In essence, a vector r (we drop the underlining here) with the Cartesian coordinates (x,y,z) is expressed in spherical coordinates by giving its distance from the origin (assumed to be identical for both systems) |r|, and the two angles and between the direction of r and the x- and z-axis of the Cartesian system. This sounds more complicated than it actually is: and are nothing but the geographic longitude and latitude. The picture below illustrates this
Simulation of SCS • http://www.flashandmath.com/mathlets/multicalc/coords/index.html
Tutorial • Evaluate: Where C is right half of the circle : x2+y2=16 Solution We first need a parameterization of the circle. This is given by, We now need a range of t’s that will give the right half of the circle. The following range of t’s will do this: Now, we need the derivatives of the parametric equations and let’s compute ds:
Tutorial ……… • The line integral is then :
Assignment No 3 • Q. No. 1: Evaluate where C is the curve shown below.
Assignment No 3: …. were C is the line segment from to • Q.NO 2: Evaluate