Rules : Everyone must attempt to answer each question.

1. Rules: • Everyone must attempt to answer each question. • Show your work on a separate sheet of paper. • Keep track of your points. • Winners receive prize. continue

3. Go BACK. You need to click on a number to proceed to the questions. Click here continue

4. Really!! Go BACK. You need to click on a number to proceed to the questions. Click here continue

6. Displacement = 27.4m + 3m -3m Distance = 27.4m + 3m +3m continue

7. 2) This object in freefall accelerates at 9.8 m/s/s. Every second the velocity changes by 9.8 m/s continue

8. A ball rolls down an incline from rest. How far does it travel in 3 seconds if it accelerates at 5 m/s2? Show Work for Credit d = vit + ½ at2 d = 0 + ½ (5 m/s2) (3s)2 d = 22.5 m continue

9. 4) Vavg = (Vf + Vi)/2 Vavg= (10m/s +25m/s)/2 Vavg = 17.5 m/s continue

10. 1) d = vit + ½ at2 -6m = ½ a (2.7s)2 a = 1.6 m/s/s down continue

11. The acceleration of a projectile is always 9.81 m/s2downward because the only force acting on the object is gravity. continue

12. 2)d = vit + ½ at2 -22m = ½ a (3.0s)2 a = 4.9 m/s/s down continue

13. VERTICAL d = vit + ½ at2 -45m = 0 + ½ (-9.81m/s2) t2 t = 3.0 s HORIZONTAL d = vit + ½ at2 d = (25 m/s)(3.0 s) + 0 d = 75 m continue Show Work for Credit

14. 2) v vs. t graphs are always linear. Slope = accel. = -9.81 m/s2 continue

15. vf = vi + at 0 = 98 m/s + (-9.81m/s2)t t = 10. s continue

16. 3) g = Fg/m continue

17. Fnet = ma 12 N = (2kg+1kg)a a = 4 m/s2 continue

18. A B C D E Which graph(s) depict an object that is accelerating? DAILY DOUBLE Select an amount of points you want to wager before going on to the question. You can only wager up to as many points as you currently have B and C only continue

19. 2) An object in equilibrium has an acceleration equal to zero. continue

20. Newton’s 3rd Law: the forces are equal in magnitude, opposite in direction. Fnail on hammer = - Fhammer on nail continue

21. Fnet = ma 50N – Ff = (4 kg)(10 m/s2) Ff= 10N continue

22. Fnet = ma Fapplied – Ffriction = 0 Fapplied= Ffriction Fapplied= μFN = (0.05)(80kg x 9.81m/s2) Fapplied= 40N continue

23. (C) If the net force is zero, the acceleration must also be zero. The slope of the speed graph = accel. = 0. Constant speed = constant slope of distance graph. continue

24. Show Work for Credit Fnet = ma Fapplied – Ffriction = 0 Fapplied = Ffriction Fapplied= μFN = (0.67)(60 N) Fapplied= 40N continue

25. Fnet = ma = 0 F – Ffriction– Fparallel = 0 F = Ffriction+ Fparallel F = Ffriction + Fg sinθ F = 3N + (10N)sin30° F= 3N + 5N F= 8N continue

26. B (4) Add vectors head to tail continue

27. List 3 scalar quantities and 3 vector quantities. Include units. DAILY DOUBLE Select an amount of points you want to wager before going on to the question. You can only wager up to as many points as you currently have Scalar: distance (m), speed (m/s), mass (kg), time (s),temp (°C) Vector: displacement (m), velocity (m/s), acceleration (m/s2), Force (N), impulse (N·s), momentum (kg·m/s) continue

28. (4) FH = Fcosθ FH =(24N)cos35° FH = 20. N FV= Fsinθ FV=(24N)sin35° FV= 14. N continue

29. A B R (1) continue

30. (4) Arrange 30N vectors to be head-to-tail, resultant starts at the tail of the first and ends at the head of the last. 30N 30N R continue