Energy Economics

1. Energy Economics A synthetic methane plant from coal is to be constructed at a cost of $4 billion dollars. It requires 14,000 tons/day of coal (10,000 Btu/lb and $15/ton mining cost) and will produce 130 MMSCF/day of synthetic methane. What is the thermal efficiency? What is the cost of coal in the produced methane ($/MMBtu)? What is the equivalent fixed cost of the plant capital cost in $/MMBtu? Assume that the plant operates 320 days per year with a 30 year life, and the selling price of the synthetic methane is $9/mm Btu. You should calculate an annualized (yearly) cost for the capital cost using an interest rate of 8%.

2. Light Bulb Economics • Building and home lighting directly affects our economy. As a nation, we spend approximately one-quarter of our electricity budget on lighting – or more than $37 billion annually An incandescent light bulb is highly inefficient because it converts only a small amount of the electrical energy into light; the rest is converted to heat. In spite of this inefficient conversion of energy, the relatively inexpensive purchase price of incandescent bulbs when compared to fluorescent lighting accounts for their popularity among consumers.

3. Heat transfer calculations indicate that the 75W incandescent bulb has a heat loss of 55W while a 20W fluorescent bulb delivers 1200 lumens with essentially no heat loss. The 75W incandescent bulb has a 750 hour life, while the 20W compact fluorescent bulb averages 10,000 hours before failing. Find out the cost of both bulbs from a local supplier and calculate the rate of return for replacing the equivalent of 20 75W lights (typical house), which are turned on an average of 4 hours/day. For an electricity price of 8 cents/kwhr and interest rate of 5%, use net present value to compare the two alternatives, and a basis of 10,000 hours of service for both types of bulbs.

6. Future value of initial payment P1 in year n: F = P1 (1 + i)n i = interest rate (%/100) Present value of future payment Fk in year k Present value of uniform future payment of 1 (3.5)

7. For non-uniform cash flows, Insulation example – capital cost vs. cost savings (Fi) annualization factor (repayment multiplier) for Fi = constant = (cash flow)

12. Table 3.2 Formulas for Evaluating Profitability (solve for i = IRR) ‘ Nomenclature • 1. i’ is the interest value of money in NPV, generally taken as the opportunity • interest that the company must forego by not investing in the next best • alternative. i is the internal rate of return. ROI, i’,and i are fractions; to • obtain %, multiply by 100. • n is the total number of time periods (normally years) between startup • (which is time zero) and end of operation of the equipment. • 3. NI= net income after taxes.

17. In the previous section we only briefly mentioned the • financial assumptions used in profitability analysis. • Any detailed analysis of a project requires specifying • the following parameters: • initial investment • future cash flows • salvage value • economic life • depreciation • depletion • investment tax credit • taxes • inflation • debt/equity ratio

18. MANUFACTURING (CASH OPERATING) REVENUE OPERATIONS SALES INCOME EXPENSES SALVAGE VALUE OPERATING INCOME (PROFIT) DEPRECIATION NET INCOME BEFORE TAXES CASH FLOW FEDERAL INCOME TAXES NET INCOME AFTER TAXES Figure 3.3 Computation of Cash Flow