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15.7 Probability Day 3. There are 2 nickels, 3 dimes, and 5 quarters. 1.) Find the probability of selecting 1 nickel, 1 dime, and 1 quarter in that order without replacement. Total = 10 P(N, D, Q) =. There are 2 nickels, 3 dimes, and 5 quarters.
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There are 2 nickels, 3 dimes, and 5 quarters 1.) Find the probability of selecting 1 nickel, 1 dime, and 1 quarter in that order without replacement. Total = 10 P(N, D, Q) =
There are 2 nickels, 3 dimes, and 5 quarters 2.) Find the probability of selecting 1 nickel, 1 dime, and 1 quarter in any order without replacement. Total = 10 (From #1): P(N, D, Q) How many ways? 3 coins, arranging 3 = 3! = 6
There are 2 nickels, 3 dimes, and 5 quarters 3.) Find the probability of selecting 1 nickel, 1 dime, and 1 quarter in any order WITH replacement. Total = 10 P(N, D, Q) = Still 6 arrangements:
A red, green, and yellow die are tossed. Find the probability: 1.) All 3 dice show a six. P(6, 6, 6) = I know, it’s creepy!!
A red, green, and yellow die are tossed. Find the probability: 2.) The green die shows an odd number and the other 2 show different even numbers. Odd #s: 1, 3, 5 Even #s: 2, 4, 6 there are 3! there are 3! Green Red Yellow
A red, green, and yellow die are tossed. Find the probability: 3.) All 3 dice show the same number. 1 1 1 or 2 2 2 or 3 3 3 or 4 4 4 or 5 5 5 or 6 6 6 Same probability for each There are 6 ways!
Standard Deck of Cards Clubs (Black) Hearts (Red) Diamonds (Red) Spades (Black) 52 cards in the deck 26 black, 26 red 4 suits: hearts, diamonds, clubs, spades 13 of each suit
Homework #7 12-5 Practice WS