250 likes | 382 Views
Find Rational Zeros. Warm Up. Lesson Presentation. Lesson Quiz. Warm-Up. Factor completely. 1. x 2 – x – 12. ( x – 4)( x + 3). ANSWER. 2. 2 x 2 – 5 x – 3. ( x – 3)(2 x + 1). ANSWER. Warm-Up. Factor completely.
E N D
Find Rational Zeros Warm Up Lesson Presentation Lesson Quiz
Warm-Up Factor completely. 1.x2–x– 12 (x– 4)(x + 3) ANSWER 2. 2x2– 5x– 3 (x – 3)(2x + 1) ANSWER
Warm-Up Factor completely. 3. Use synthetic division to divide2x3– 3x2– 18x– 8 by x– 4. 2x2 + 5x + 2 ANSWER The volume of a box is modeled byf (x) = x(x– 1)(x– 2), where x is the length in meters. What is the volume when the length is 3 meters? 4. ANSWER 6m3
4 12 1 2 6 3 Possible rational zeros:+ , + , + , + , + , + 1 1 1 1 1 1 Example 1 List the possible rational zeros of f using the rational zero theorem. a. f (x) = x3 + 2x2 – 11x + 12 Factors of the constant term: + 1, + 2, + 3, + 4, + 6, + 12 Factors of the leading coefficient:+ 1 Simplified list of possible zeros:+ 1, + 2, + 3, + 4, + 6, + 12
Possible rational zeros: 2 1 5 10 1 2 5 10 2 5 1 + , + , + , + , + , + , + , + , + , + , + 4 2 2 4 2 2 4 1 1 1 1 + 10 4 1 Simplified list of possible zeros:+ 1, + 2, + 5, + 10, + , + , + 2 + 5 1 5 2 4 4 Example 1 b. f (x) = 4x4 – x3 – 3x2 + 9x – 10 Factors of the constant term: + 1, + 2, + 5, + 10 Factors of the leading coefficient:+ 1, + 2, + 4
Guided Practice List the possible rational zeros of fusing the rational zero theorem. 1. f (x) = x3 + 9x2 + 23x + 15 ANSWER + 1, + 3, + 5 + 15 2. f (x) =2x3 + 3x2 – 11x – 6 1 3 + + 1, + 2, + 3, + 6, + , ANSWER 2 2
List the possible rational zeros. The leading coefficient is 1 and the constant term is 20. So, the possible rational zeros are: 2 10 x = + , + , + , + , + , + 5 20 4 1 1 1 1 1 1 1 Example 2 Find all real zeros off (x) = x3 – 8x2 + 11x + 20. SOLUTION STEP 1
Test x =1: 1 1 – 8 11 20 1 – 7 4 1 – 7 4 24 ↑ 1 is not a zero. Test x = –1: –1 1 –8 11 20 –1 9 –20 1 – 9 20 0 ↑ –1 is a zero Example 2 STEP 2 Test these zeros using synthetic division.
ANSWER The zeros of fare –1, 4, and 5. Example 2 Because –1 is a zero of f, you can write f (x) = (x + 1)(x2 – 9x + 20). STEP 3 Factor the trinomial in f (x) and use the factor theorem. f (x) = (x + 1) (x2 – 9x + 20) = (x + 1)(x – 4)(x – 5)
Guided Practice Find all real zeros of the function. 3.f (x) = x3 – 4x2 – 15x + 18 –3, 1, 6 ANSWER 4. f (x) = x3 – 8x2 + 5x+ 14 –1, 2, 7 ANSWER
List the possible rational zeros of f : 1 3 + , + , + , + , + , + , , + 6 12 + 1 , + 1 2 3 4 1 1 1 1 2 1 1 2 5 2 3 ,+ , +, + , + , +, + , + 3 4 12 1 6 5 5 5 5 5 10 10 Example 3 Find all real zeros off (x) =10x4 – 11x3 – 42x2 + 7x + 12. SOLUTION STEP 1
Choose reasonable values from the list above to check using the graph of the function. For f, the values 3 12 3 1 x = – , x = – , x = , andx = 2 5 2 5 are reasonable based on the graph shown at the right. Example 3 STEP 2
3 – 10 –11 –42 7 12 2 9 69 –15 39 – 4 2 21 23 10 – 26 – 3 – 4 2 –1 10 – 11 – 42 7 12 2 – 5 8 17 –12 10 – 16 – 34 24 0 ↑ 1 – is a zero. 2 Example 3 STEP 3 Check the values using synthetic division until a zero is found.
1 f (x) = x + (10x3 – 16x2 – 34x + 24) 2 1 = x + (2)(5x3 – 8x2 – 17x + 12) 2 Example 3 STEP 4 Factor out a binomial using the result of the synthetic division. Write as a product of factors. Factor 2 out of the second factor. = (2x +1)(5x3 – 8x2 – 17x +12) Multiply the first factor by2.
Repeat the steps above for g(x) = 5x3 – 8x2 – 17x + 12. Any zero of g will also be a zero of f. The possible rational zeros of gare: 12 1 3 4 6 2 x = + 1, + 2, + 3, + 4, + 6, + 12, + , + , + , + , + , + 5 5 5 5 5 5 3 The graph of gshows that may be a zero. Synthetic division shows that is a zero and 5 3 5 3 g (x) = x – (5x2 – 5x – 20) 5 It follows that: f (x) = (2x + 1) g (x) Example 3 STEP 5 = (5x – 3)(x2 – x – 4). = (2x + 1)(5x – 3)(x2 – x – 4)
x = –(–1) +√ (–1)2 – 4(1)(–4) 2(1) x = 1 +√17 2 Example 3 Find the remaining zeros of f by solving x2 – x – 4 = 0. STEP 6 Substitute 1 for a, –1for b, and –4 for cin the quadratic formula. Simplify. ANSWER 1 3 The real zeros of f are , , 1 + √17, and1 – √17. – 2 5 2 2
3 1 3 1 6 2 2 4 ANSWER – , , Guided Practice Find all real zeros of the function. 5. f (x) = 48x3+ 4x2 – 20x + 3 6. f (x) = 2x4 + 5x3 – 18x2 – 19x + 42 ANSWER – 2, , 1+2 √2
Some ice sculptures are made by filling a mold with water and then freezing it. You are making such an ice sculpture for a school dance. It is to be shaped like a pyramid with a height that is 1 foot greater than the length of each side of its square base. The volume of the ice sculpture is 4 cubic feet. What are the dimensions of the mold? Example 4 ICE SCULPTURES
1 4 = x2(x + 1) 3 Example 4 SOLUTION Write an equation for the volume of the ice sculpture. STEP 1 Write equation. 12 = x3 + x2 Multiply each side by 3 and simplify. 0 = x3 + x2 – 12 Subtract 12 from each side.
List the possible rational solutions: 1 2 3 4 6 12 + , + , + , + ,+ , + 1 1 1 1 1 1 1 1 1 0 –12 1 2 2 1 2 2 –10 Example 4 STEP 2 Test possible solutions. Only positive x-values make sense. STEP3
2 1 1 0 –12 2 6 12 1 3 6 0 ↑ 2is a solution. Check for other solutions. The other two solutions, which satisfy –3 +i √15 x2 + 3x + 6 = 0, arex = and can be discarded because they are imaginary numbers. 2 Example 4 STEP 4
ANSWER The only reasonable solution isx = 2. The base of themold is2feet by2feet. The height of the mold is2 + 1 = 3feet. Example 4
7. WHAT IF? In Example 4, suppose the base of the ice sculpture has sides that are 1 foot longer than the height. The volume of the ice sculpture is 6cubicfeet. What are the dimensions of the mold? ANSWER Base side: 3 ft, height: 2 ft Guided Practice
ANSWER + 1, + 2, + 4 ANSWER –2, 1, 4 Lesson Quiz 1. List the possible rational zeros of f(x) = x3 + 8x2 – x + 4. Find all real zeros of the functions 2. f(x) = x3 – 3x2 – 6x + 8.
ANSWER 5 –3, 2, 2 4. The volume V of a storage shed with a triangular roof can be modeled by V = x3 + x2(6 – x). If the volume of the shed is 80 cubic feet, find x. 1 2 ANSWER 4 Lesson Quiz 3. f(x) = 2x3 – 3x2 – 17x + 30.