1 / 67

Forces Worksheets ( Part 2 )

Forces Worksheets ( Part 2 ). 1A ) Box A is 50kg and Box B is 150 kg. Which box has more inertia? B) What is the mass and weight of box A on earth? ( g moon = 1.6 m/s 2 down) Mass: ____________ Weight: _____________

ginger-franco
Download Presentation

Forces Worksheets ( Part 2 )

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Forces Worksheets (Part 2) 1A) Box A is 50kg and Box B is 150 kg. Which box has more inertia? B) What is the mass and weight of box A on earth? (gmoon= 1.6 m/s2 down) Mass: ____________ Weight: _____________ c) What is the mass and weight of box A on the moon? (gmoon= 1.6 m/s2 down) Mass: ____________ Weight: _____________

  2. Forces Worksheets (Part 2) 1A) Box A is 50kg and Box B is 150 kg. Which box has more inertia? B) What is the mass and weight of box A on earth? (gmoon= 1.6 m/s2 down) Mass: ____________ Weight: _____________ c) What is the mass and weight of box A on the moon? (gmoon= 1.6 m/s2 down) Mass: ____________ Weight: _____________

  3. Law of Ones A way to answer a question like this: If the force acting on a cart triples, what happens to the cart's acceleration? #1 Start by picking the equation: F=ma

  4. Law of Ones #2 m

  5. Law of Ones #3 Set up: equation with changes over equation with ones With changes (or in other words multipliers) With no changes (or in other words 1 times what it was)

  6. #4 Calculate With changes (or in other words multipliers) With no changes (or in other words 1 times what it was)

  7. Law of Ones • If the force acting on a cart triples, what happens to the cart's acceleration? Acceleration would triple

  8. Extension Law of Ones • Rephrased question that requires an additional step • The acceleration of a car was 20 m/s2. If the force acting on a cart tripled, what is the cart's new acceleration? If the original acceleration was 20 m/s2the new acceleration would be (20 m/s2 x 3 = 60 m/s2)

  9. 3. How does the force on an object change if the acceleration is 3 times the original?

  10. 3. How does the force on an object change if the acceleration is 3 times the original?

  11. 4. How much does the acceleration of an object change if you triple the force on and double the mass of the object?

  12. 4. How much does the acceleration of an object change if you triple the force on and double the mass of the object?

  13. State the following Law 4A) Newtons First Law : 4B) Newtons Second Law: 4C) Newtons Third Law:

  14. State the following Law 4A) Newton’s First Law : (Inertia) • An object in motion stays in motion and an object at rest stays at rest unless acted upon by an outside force 4B) Newton’s Second Law: (F=ma) • Force causes acceleration based on mass 4C) Newton’s Third Law: (Action Reaction) • For every action force, there is an equal reaction force in the opposite direction

  15. 5A) A glass of water is sitting on a table covered by a tablecloth. Explain using physics terms (i.e. inertia) why a magician can pull the tablecloth from underneath the cloth without moving the glass. 5B) Which of Newton’s laws is the previous question (5A) the most related to?

  16. 5A) A glass of water is sitting on a table covered by a tablecloth. Explain using physics terms (i.e. inertia) why a magician can pull the tablecloth from underneath the cloth without moving the glass. The objects on the table want to stay at rest 5B) Which of Newton’s laws is the previous question (5A) the most related to? Newton’s First Law

  17. 6A) What is the reaction force to a player hitting a baseball with a bat? 6B) What is the reaction force of the earth pulling a leaf that fell from a tree down? 6C) 58 kg Joe jumps off of his 1.5 kg skate board. Joe accelerates at 2.1 m/s2 to the right. What is the magnitude and direction of the skateboards acceleration? 6D) Which of Newton’s Laws are questions 6A, B, and C most related to?

  18. 6A) What is the reaction force to a player hitting a baseball with a bat? 6B) What is the reaction force of the earth pulling a leaf that fell from a tree down? 6C) 58 kg Joe jumps off of his 1.5 kg skate board. Joe accelerates at 2.1 m/s2 to the right. What is the magnitude and direction of the skateboards acceleration? 6D) Which of Newton’s Laws are questions 6A, B, and C most related to?

  19. 7A) What is the net force on the 15kg box to the right? 7B) What would the acceleration be when the two forces are present on the box above? 7C) How far would the 15 kg box travel if it started from rest and reached a speed of 20 m/s?

  20. 7A) What is the net force on the 15kg box to the right? 7B) What would the acceleration be when the two forces are present on the box above? 7C) How far would the 15 kg box travel if it started from rest and reached a speed of 20 m/s?

  21. 7A) What is the net force on the 15kg box to the right? 7B) What would the acceleration be when the two forces are present on the box above? 7C) How far would the 15 kg box travel if it started from rest and reached a speed of 20 m/s?

  22. 8A) A constant forward net force of 530 N is applied to a bicycle and a rider with a total mass of 110 kg. How fast will the bicycle be travelling after 4 seconds if starting from rest?

  23. 8A) A constant forward net force of 530 N is applied to a bicycle and a rider with a total mass of 110 kg. How fast will the bicycle be travelling after 4 seconds if starting from rest?

  24. 8A) A constant forward net force of 530 N is applied to a bicycle and a rider with a total mass of 110 kg. How fast will the bicycle be travelling after 4 seconds if starting from rest?

  25. 8A) A constant forward net force of 530 N is applied to a bicycle and a rider with a total mass of 110 kg. How fast will the bicycle be travelling after 4 seconds if starting from rest?

  26. 9A) A skydiver with a weight of 350 N is falling through the sky. At one point in time the air resistance acting on him is 130 N. What is the skydiver’s acceleration at this point?

  27. 9A) A skydiver with a weight of 350 N is falling through the sky. At one point in time the air resistance acting on him is 130 N. What is the skydiver’s acceleration at this point?

  28. 9A) A skydiver with a weight of 350 N is falling through the sky. At one point in time the air resistance acting on him is 130 N. What is the skydiver’s acceleration at this point?

  29. 9A) A skydiver with a weight of 350 N is falling through the sky. At one point in time the air resistance acting on him is 130 N. What is the skydiver’s acceleration at this point?

  30. 9A) A skydiver with a weight of 350 N is falling through the sky. At one point in time the air resistance acting on him is 130 N. What is the skydiver’s acceleration at this point?

  31. 9B) A skydiver with a weight of 350 N pulls his parachute and air resistance increases to 600N. What is the skydiver’s acceleration at this point?

  32. 9B) A skydiver with a weight of 350 N pulls his parachute and air resistance increases to 600N. What is the skydiver’s acceleration at this point?

  33. 9B) A skydiver with a weight of 350 N pulls his parachute and air resistance increases to 600N. What is the skydiver’s acceleration at this point?

  34. 9B) A skydiver with a weight of 350 N pulls his parachute and air resistance increases to 600N. What is the skydiver’s acceleration at this point?

  35. 9C) What is the net force on a sky diver that reaches terminal velocity? 9D) What is the air resistance force present if a 250N individual was falling at terminal velocity? 9E) What is acceleration of a sky diver that reaches terminal velocity?

  36. 9C) What is the net force on a sky diver that reaches terminal velocity? 9D) What is the air resistance force present if a 250N individual was falling at terminal velocity? 9E) What is acceleration of a sky diver that reaches terminal velocity?

  37. 10A) What force is required to push a crate with 200N of frictional force uniformly forward? 10b) What net force is required to push a crate with 200N of frictional force uniformly forward?

  38. 10A) What force is required to push a crate with 200N of frictional force uniformly forward? 10b) What net force is required to push a crate with 200N of frictional force uniformly forward?

  39. 10A) What force is required to push a crate with 200N of frictional force uniformly forward? 10b) What net force is required to push a crate with 200N of frictional force uniformly forward?

  40. 11) If the force acting on a cart doubles, what happens to the cart's acceleration?

  41. 11) If the force acting on a cart doubles, what happens to the cart's acceleration?

  42. Apparent Weight 12) When would you feel heavier inside an elevator? (Accelerating up or down?) 13) When would you feel lighter inside an elevator? (Accelerating up or down?)

  43. Apparent Weight 12) When would you feel heavier inside an elevator? (Accelerating up or down?) 13) When would you feel lighter inside an elevator? (Accelerating up or down?)

  44. Tension lesson If an object is hanging straight down in equilibrium (Fnet=0) (or with no acceleration) from one rope the tension in the rope is equal to the objects weight.

  45. Tension Lesson • If the object is hanging straight down from more ropes you need to divide the weight (Fw) by the number of ropes.

  46. Tension at an angle • Tension in the rope increases as the angle from the vertical increases. • If the rope is at an angle

  47. To solve for the tension in a single rope #1 draw a triangle with the vertical side being equal to the objects weight. Solve for weight if only mass was given.Then solve for the hypotenuse which would be the tension in the rope. Using SOH CAH TOA

  48. To solve for the tension in a single rope #1 draw a triangle with the vertical side being equal to the objects weight. Solve for weight if only mass was given.Then solve for the hypotenuse which would be the tension in the rope. Using SOH CAH TOA

  49. To solve for the tension in a single rope #1 draw a triangle with the vertical side being equal to the objects weight. Solve for weight if only mass was given.Then solve for the hypotenuse which would be the tension in the rope. Using SOH CAH TOA

  50. To solve for the tension in a single rope #1 draw a triangle with the vertical side being equal to the objects weight. Solve for weight if only mass was given.Then solve for the hypotenuse which would be the tension in the rope. Using SOH CAH TOA

More Related