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Chapter 16 & 17 Discussion. Meso = identical. Endo and exo are meaningless without substitutents to provide frame of reference. diene. dienophile. Recognize that this is a Diels Alder reaction by the diene and dienophile (on the right). 2) Draw a cyclohexene ring.
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Meso = identical Endo and exo are meaningless without substitutents to provide frame of reference
diene dienophile Recognize that this is a Diels Alder reaction by the diene and dienophile (on the right) 2) Draw a cyclohexene ring 3) Build models of the possible isomers that could result from the cycloaddition 4) Use resonance to help predict regioisomer 5) Temperature for endo/exo preference.
endo exo 3) Build models of the possible isomers that could result from the cycloaddition 4) Use resonance to help predict regioisomer 5) Temperature for endo/exo preference.
Endo and exo + enantiomer + enantiomer Exo (thermodynamic product) Endo (kinetic product)
? Recognize that this is a Diels Alder reaction by the diene and dienophile (on the right) 2) Draw a cyclohexene ring 3) Build models of the possible isomers that could result from the cycloaddition 4) Use resonance to help predict regioisomer 5) Temperature for endo/exo preference.
Four possible regioisomers and diastereomers (+ enantiomers)
Aromatic if 2, 6, 10, 14, 18 pi electrons….. Anti-aromatic if 4, 8, 12, 16, ….. pi electrons If neither then not aromatic or anti-aromatic. Anti-aromatic more stable than expected. Anti-aromatic – less stable and likely will not form at all.
Cyclopropenyl anion 4 pi electrons. Antiaromatic
Cyclopentadienyl anion 6 pi electrons, aromatic
Azulene Yarrow chamomile 10 pi electrons aromatic Lactariusazulene
Naphthalene aromatic : cyclic, 10 electrons, flat, conjugated
naphthalene Azulene Why is naphthalene nonpolar and azulene polar?
Aromatic, anti-aromatic or neither? 8 pi electrons Depends on conformation. If flat and fully conjugated, antiaromatic!!!! Lower energy conformation (than anti-aromatic) is not flat