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Estudio del movimiento

Estudio del movimiento. U.2 Dinámica. Ejercicio 5 de recapitulación página 174. F = −4,2 j N. F = −4,2 j N.

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Estudio del movimiento

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  1. Estudio del movimiento U.2 Dinámica Ejercicio 5 de recapitulación página 174

  2. F = −4,2j N F = −4,2j N Un balón de fútbol de 428 g tiene una velocidad v = 20 i + 14 j. Cuál será su velocidad 2 s después, teniendo en cuenta que la atracción gravitatoria supone una fuerza de −4,2 j N. vi = 20 i + 14 j m/s FINAL INICIAL vj = (20 i− 5,6 j) m/s La fuerza que actúa sobre el cuerpo provoca una variación de momento lineal: Dp = SF·Dt = −4,2 j· 2 kgm/s = −8,4 jkgm/s Dp = 0,428(vf − 20 i− 14 j) = −8,4 j kgm/s vf = 20 i − 5,6 j m/s

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