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Homework questions thus far???. Section 4.10? 5.1? 5.2?. The Definite Integral. Chapters 7.7, 5.2 & 5.3 January 30, 2007. Estimating Area vs Exact Area. Pictures. Riemann sum rectangles, ∆ t = 4 and n = 1:. Better Approximations. Trapezoid Rule uses straight lines.
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Homework questions thus far??? • Section 4.10? • 5.1? • 5.2?
The Definite Integral Chapters 7.7, 5.2 & 5.3 January 30, 2007
Pictures Riemann sum rectangles, ∆t = 4 and n = 1:
Better Approximations • Trapezoid Rule uses straight lines
Better Approximations • The Trapezoid Rule uses small lines • Next highest degree would be parabolas…
Simpson’s Rule Mmmm…parabolas… Put a parabola across each pair of subintervals:
Simpson’s Rule Mmmm…parabolas… Put a parabola across each pair of subintervals: So n must be even!
Simpson’s Rule Formula Like trapezoidalrule
Simpson’s Rule Formula Divide by 3instead of 2
Simpson’s Rule Formula Interiorcoefficientsalternate: 4,2,4,2,…,4
Simpson’s Rule Formula Second from start and endare both 4
Simpson’s Rule • Uses Parabolas to fit the curve • Where n is even and ∆x = (b - a)/n • S2n=(Tn+ 2Mn)/3
Use Simpson’s Rule to Approximate the definite integral with n = 4 g(x) = ln[x]/x on the interval [3,11] Use T4.
Runners: A radar gun was used to record the speed of a runner during the first 5 seconds of a race (see table) Use Simpsons rule to estimate the distance the runner covered during those 5 seconds.
Definition of Definite Integral: If f is a continuous function defined for a≤x≤b, we divide the interval [a,b] into n subintervals of equal width ∆x=(b-a)/n. We let x0(=a),x1,x2,…,xn(=b) be the endpoints of these subintervals and we let x1*, x2*, … xn* be any sample points in these subintervals so xi*lies in the ith subinterval [xi-1,xi]. Then the Definite Integral of f from a to b is:
Properties of the Integral 1) 2) = 0 3) for “c” a constant
Properties of the Definite Integral • Given that: • Evaluate the following:
Properties of the Definite Integral • Given that: • Evaluate the following:
Integral Defined Functions Let f be continuous. Pick a constant a. Define:
Integral Defined Functions Let f be continuous. Pick a constant a. Define: Notes: • lower limit a is a constant.
Integral Defined Functions Let f be continuous. Pick a constant a. Define: Notes: • lower limit a is a constant. • Variable is x: describes how far to integrate.
Integral Defined Functions Let f be continuous. Pick a constant a. Define: Notes: • lower limit a is a constant. • Variable is x: describes how far to integrate. • t is called a dummy variable; it’s a placeholder
Integral Defined Functions Let f be continuous. Pick a constant a. Define: Notes: • lower limit a is a constant. • Variable is x: describes how far to integrate. • t is called a dummy variable; it’s a placeholder • F describes how much area is under the curve up to x.
Example Let . Let a = 1, and . Estimate F(2) and F(3).
Example Let . Let a = 1, and . Estimate F(2) and F(3).
Where is increasing and decreasing? is given by the graph below: F is increasing. (adding area) F is decreasing. (Subtracting area)
Fundamental Theorem I Derivatives of integrals: Fundamental Theorem of Calculus, Version I: If f is continuous on an interval, and a a number on that interval, then the function F(x) defined by has derivative f(x); that is, F'(x) = f(x).
Example Suppose we define .
Example Suppose we define . Then F'(x) = cos(x2).
Example Suppose we define . Then F'(x) =
Example Suppose we define . Then F'(x) = x2 + 2x + 1.
Fundamental Theorem of Calculus (Part 1) • If f is continuous on [a, b], then the function defined by • is continuous on [a, b] and differentiable on (a, b) and
Fundamental Theorem of Calculus (Part 1)(Chain Rule) • If f is continuous on [a, b], then the function defined by • is continuous on [a, b] and differentiable on (a, b) and
1. Find: In-class Assignment 2. Estimate (by counting the squares) the total area between f(x) and the x-axis. Using the given graph, estimate Why are your answers in parts (a) and (b) different?
Consider the function f(x) = x+1 on the interval [0,3] • First let the bottom bound = 1, if x >1, we calculate the area using the formula for trapezoids:
Consider the function f(x) = x+1 on the interval [0,3] • Now calculate with bottom bound = 1, and x < 1, :
Consider the function f(x) = x+1 on the interval [0,3] • So, on [0,3], we have that • And F’(x) = x + 1 = f(x) as the theorem claimed! Very Powerful! Every continuous function is the derivative of some other function! Namely: